Is this math? if so let me know maybe I could try to help
I am not sure about this but here goes nothing: d=2.5t+2.2 is very familiar to y=mx+b y=d m=2.5 x=t b=2.2 to find a new quasion we substitute d and t into place wich equals 1=2.5(0)+b simplification and you get b=1 so your answer is d=2.5t+1
We are given dimensions of rectangular bedroom = length of 5m and width 3 m.
Also scale drawing of factor 1/50 of the original dimension.
In order to find the dimensions of scale drawing, we need to multiply scale factor by each dimension.
Therefore, length of the scale drawing is 5 * 1/50 = 1/10 m and
Let us convert it in centimeter now.
1 m = 100 cm
1/10 m = 100 * 1/10 = 10cm.
Width of the scale drawing = 3 * 1/50 = 3/50 m.
100*3/50 = 6 cm.
Therefore, the dimensions of a scale drawing of Elenas bedroom is length 10cm and width 6cm.
Answer:
Step-by-step explanation:
To find the zeros of the quadratic function f(x)=6x^2 + 12x – 7 we need to factorize the polynomial.
To do so, we need to use the quadratic formula, which states that the solution to any equation of the form ax^2 + bx + c = 0 is:
So, the first thing we're going to do is divide the whole function by 6:
6x^2 + 12x – 7 = 0 -> x^2 + 2x - 7/6
This step is optional, but it makes things quite easier.
Then we using the quadratic formula, where:
a=1, b= 2, c = -7/6.
Then:
So the zeros are:
Answer:
a. 205320
b. 34220
c. 60! / (35)! (25)! + 60!/ (40)!(20)! + 60!/ (45)! (15)!
Step-by-step explanation:
a) The number of ways to dustribute exams among the TA's is:
n / (n - r)!
n= number of things to choose from
r= Choosing r number
60P3= 60! / (60 - 3)!
(60)(59)(58)(57)! / (57)!
=205320
B) The number of ways to dustribute the exams among the TA's is:
n! /(n - r)! r!
60C3= 60! /(60 - 3)! 3!
= 60!/ 57! 3!
= 60 × 59 × 58 / 3 × 2 × 1
= 34220
C) The required number of ways is:
60C25 + 60C20 + 60C15
= 60! / (35)! (25)! + 60!/ (40)!(20)! + 60!/ (45)! (15)!
