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2 years ago

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1.Los neumáticos de un coche deben estar, a 20 ºC, a una presión de 1'8 atm. Con el movimiento, se calientan hasta 50 ºC, pasand

o su volumen de 50 a 50'5 litros. ¿Cuál será la presión del neumático tras la marcha?

1 answer:

boyakko [2]2 years ago

3 0

Answer:

do you mind translating it

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A patient needs 0.024g of a sulfa drug. There are 8 mg tablets in stock. How many tablets should be given?

Varvara68 [4.7K]

3 tablets. there are 1000 mg in a g so youd need 24 mg and 8x3=24

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2 years ago

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You are tired at the end of the term and decide to borrow $500 to go on a trip to whatever land. You go to the bank and borrow t

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Answer:

A)55

B)110

Step-by-step explanation:500 /11%=55

55*2=110

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2 years ago

Suppose that the researchers wanted to estimate the mean reaction time to within 6 msec with 95% confidence. Using the sample st

Lisa [10]

Answer:

a) The 95% confidence interval would be given by (509.592;550.308)

b) n=523 rounded up to the nearest integer

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=530$ represent the sample mean for the sample

$\mu$ population mean

s=70 represent the sample standard deviation

n=48 represent the sample size (variable of interest)

Confidence =95% or 0.995

Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are df=n-1=48-1=47

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,47)".And we see that $z_{\alpha/2}=2.01$

Now we have everything in order to replace into formula (1):

$530-2.01\frac{70}{\sqrt{48}}=509.692$

$530+2.01\frac{70}{\sqrt{48}}=550.308$

So on this case the 95% confidence interval would be given by (509.592;550.308)

Part b

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

Assuming that $\hat \sigma =s$

And on this case we have that ME =6msec, and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 95% of confidence interval is provided, $z_{\alpha/2}=1.96$ , replacing into formula (b) we got:

$n=(\frac{1.96(70)}{6})^2 =522.88 \approx 523$

So the answer for this case would be n=523 rounded up to the nearest integer

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2 years ago

Which equation is y=3(x-2)^2-(x-5)^2 rewritten in vertex form?

Misha Larkins [42]

The question does not present the options, but this does not interfere with the resolution

we have that
y=3(x-2)²-(x-5)²
y=3(x²-4x+4)-(x²-10x+25)
y=3x²-12x+12-x²+10x-25
y=(3x²-x²)+(-12x+10x)+(12-25)
y=2x²-2x-13
y+13=2x²-2x
y+13=2(x²-x)
y+13+0.50=2(x²-x+0.25)
y+13.50=2(x-0.5)²------> this is the equation in the vertex form

the vertex is the point (0.5,-13.50)

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liberty middle school is holding a fundraiser the sixth graders have raised 52% of thier goal amount the seventh and eighth grad

mario62 [17]

6th graders = 52%
7th graders = 0.57x100 = 57%
8th graders = 2/5 x 100 = 40% so least to greatest will be

8th, 6th then 7th

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