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2 years ago

Mario’s speed while riding his bike is shown in the graph.

Mathematics

2 answers:

Tamiku [17]2 years ago

7 0

Answer:

Step-by-step explanation:

V125BC [204]2 years ago

4 0

Answer:

I believe that it is C.

Step-by-step explanation:

Amanda's speed is 9 mph because 18 divided by 2 is 9.

Marcos speed is 8 mph because you can work backwards from the graph from the second point of (2, 16) to (1, 8) and find the difference of 1, and 8.

The slope is therefore 8.

Amanda's speed is 9 mph and Marco's speed is 8 mph. I think you know the answer from the previous statement.

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On sunday 1/16 people who visit were senior citizens, 3/16 were infants, 3/8 were children and 3/8 were adults, how many of each

mamaluj [8]

Answer:

Out of total people visited the zoo on Sunday , 6.25% was senior citizen , 18.75% were infants , 35% were children and 35% were adult.

Step-by-step explanation:

let total number of people visited the group = x

so number of senior citizens = x × 1/16 = x/16

Percentage of senior citizens = (number of senior citizens ÷ total number of people visited the group) × 100

= (x/16 ÷ x) × 100 = 100/16 = 6.25%

number of infants = 3/16 × x = 3x/16

Percentage of infants =(number of infants ÷ total number of people visited the group) × 100 = (3x/16 ÷ x) × 100 = 300/16 = 18.75%

number of children = 3/8 × x = 3x/8

Percentage of children =(number of children ÷ total number of people visited the group) × 100 = (3x/8 ÷ x) × 100 = 300/8 = 37.5%

number of adults = 3/8 × x = 3x/8

Percentage of adults =(number of adults ÷ total number of people visited the group) × 100 = (3x/8 ÷ x) × 100 = 300/8 = 37.5%.

Hence we can conclude that Out of total people visited the zoo on Sunday , 6.25% was senior citizen , 18.75% were infants , 35% were children and 35% were adult.

4 0

2 years ago

Lightning strikes earth 1000 times in 10 sec. how many times does lightning strike per sec?

atroni [7]

Simple division:

The amount/number of seconds=amount per second.

1000/10=100

Lightning strikes earth 100 times per second.

6 0

2 years ago

A cube-shaped water tank having 6 ft side lengths is being filled with water. The bottom is solid metal but the sides of the tan

Mekhanik [1.2K]

Answer:

0.033 ft

Step-by-step explanation:

Let g = 32.2 ft/s2 and h be the maximum height that water can be filled before the sides shatter.

Pressure is distributed from 0 to maximum at the bottom like the following equation:

$P = \rho gh$

So the force generated by water pressure on the side of the tank is

$F = PA = \rho ghs/2$

where s = 6ft is the side length of the tank. This force cannot be larger than 200lb

$\rho ghs/2 \leq 200$

$62.4*32.2*h*6/2 \leq 200$

$h \leq 0.033 ft$

4 0

2 years ago

Find the mean, median and mode of the weights of the people shown. 105kg 53kg 76kg 91kg 120kg 61kg 55kg 98kg 61kg

Yuliya22 [10]

First, you need to put them in order
53kg, 55kg, 61kg, 61kg, 76kg, 91kg, 98kg, 105kg, 120kg

For mean, you add them all up and divide by the amount of numbers (9)
720/9 = 80

For median, you find the middle number (76kg)

For mode, you find the number that appears the most (61kg)

Mean: 80
Median: 76
Mode: 61

5 0

2 years ago

Read 2 more answers

The Acme Candy Company claims that 60% of the jawbreakers it produces weigh more than 0.4 ounces. Suppose that 800 jawbreakers

vichka [17]

Answer:

Yes, it would be statistically significant

Step-by-step explanation:

The information given are;

The percentage of jawbreakers it produces that weigh more than 0.4 ounces = 60%

Number of jawbreakers in the sample, n = 800

The mean proportion of jawbreakers that weigh more than 0.4 = 60% = 0.6 = $\mu _ {\hat p}$ =p

The formula for the standard deviation of a proportion is $\sigma _{\hat p} =\sqrt{\dfrac{p(1-p)}{n} }$

Solving for the standard deviation gives;

$\sigma _{\hat p} =\sqrt{\dfrac{0.6 \cdot (1-0.6)}{800} } = 0.0173$

Given that the mean proportion is 0.6, the expected value of jawbreakers that weigh more than 0.4 in the sample of 800 = 800*0.6 = 480

For statistical significance the difference from the mean = 2× $\sigma _{\hat p}$ = 2*0.0173 = 0.0346 the equivalent number of Jaw breakers = 800*0.0346 = 27.7

The z-score of 494 jawbreakers is given as follows;

$Z=\dfrac{x-\mu _{\hat p} }{\sigma _{\hat p} }$

$Z=\dfrac{494-480 }{0.0173 } = 230.94$

Therefore, the z-score more than 2 × $\sigma _{\hat p}$ which is significant.

8 0

2 years ago