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2 years ago

In 2009, a city with a population of 796,000 had 2,388 births. What is the number of births per 10,000 in the city?

Mathematics

1 answer:

Tom [10]2 years ago

7 0

796,000/2388=10,000/x
796,000x= (2388*10,000)
796,000x/796,000=23,880,000/796,000
x=30 births

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At the time of her grandson's birth, a grandmother deposits $12,000.00 in an account that pays 2% compound monthly. What will be that value of the account at the child's twenty-first birthday, assuming that no other deposits or withdrawls are made during the period.
---
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2 years ago

Read 2 more answers

Malia split up the large container of salsa that she bought into 5 bowls to place around her house for the party if each Bowl co

Hoochie [10]

Answer:

You never gave the answer choices but it should look something like this.

5 ⋅ 8.5 = x

x / 5 = 8.5

as for x. X=42.5

3 0

2 years ago

Leah decided to paint some of the rooms at her 51-room hotel. She needs 1/5 of a can of paint per room. If Leah had 6 cans of pa

netineya [11]

Answer:

Leah can paint 30 rooms.

Step-by-step explanation:

Each room requires $\dfrac{1}{5}$ of a can of paint, this means painting 5 rooms requires

$\dfrac{1}{5}+\dfrac{1}{5}+\dfrac{1}{5}+\dfrac{1}{5}+\dfrac{1}{5}=\dfrac{1+1+1+1+1}{5}=\dfrac{5}{5} =1$

or 1 can paints 5 rooms.

So, if Leah has 6 cans of paint, then how many rooms can she paint?

Leah can paint

$\dfrac{5\:rooms}{can} *6\:cans=\boxed{30\: rooms}$

Leah can paint 30 rooms with 6 cans of paint.

5 0

1 year ago

Suppose we want to choose 2 objects, without replacement, from the 5 objects pencil, eraser, desk, chair, and lamp. (a)How many

BigorU [14]

Answer:

a) 20 ways

b) 10 ways

Step-by-step explanation:

When the order of selection/choice matters, we use Permutations to find the number of ways and if the order of selection/choice does not matter, we use Combinations to find the number of ways.

Part a)

We have to chose 2 objects from a group of 5 objects and order of choice matters. This is a problem of permutations, so we have to find 5P2

General formula of permutations of n objects taken r at time is:

$nPr=\frac{n!}{(n-r)!}$

Using the value of n=5 and r=2, we get:

$5P2=\frac{5!}{(5-2)!} =20$

Therefore, we can choose 2 objects from a group of 5 given objects if the order of choice matters.

Part b)

Order of choice does not matter in this case, so we will use combinations to find the number of ways of choosing 2 objects from a group of 5 objects which is represented by 5C2.

The general formula of combinations of n objects taken r at a time is:

$nCr=\frac{n!}{r!(n-r)!}$