The summation indicates the sum from n = 1 to n = 3 of the expression 2(n+5).
2 (n+5) = 2n + 10
2n + 10 denotes an Arithmetic Series, with a common difference of two and first term as 12.
For n =1, it equals 12
For n = 2, it equals 14
For n = 3, it equals 16
So the sum from n=1 to n=3 will be 12 + 14 + 16 = 42
Sum of an Arithmetic Series can also be written as:
Using the value of a₁ and d, we can simplify the expression as:
This expression is equivalent to the given expression and will yield the same result.
For n=3, we get the sum as:
S₃ = 3(11+3) = 42
Hey!
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Let's Solve A:
1/2 = 0.5
0.5 + 0.30 = 0.80
a = 0.80
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Let's Solve B:
3/4 = 0.75
0.10 + 0.75 = 0.85
b = 0.85
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Let's Solve C:
1/3 ≈ 0.33
0.33 + 0.50 = 0.83
c = 0.83
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Let's Solve D:
1/3 ≈ 0.33
0.33 + 0.40 = 0.73
d = 0.73
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Answer:
By solving each equation we can see that option A has the lowest value!
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Hope This Helped! Good Luck!
Hello,
A good first step to take would be to calculate how much of a barrel John and Mary can drink together in 1 day.
If John can drink 1 barrel in 6 days, then every day he can drink 1/6 of a barrel.
If Mary can drink 1 barrel in 12 days, then every day she can drink 1/12 of a barrel.
Every day, the total that John and Mary can drink will be (1/6) + (1/12) = (1/4) of a barrel.
If we want to know how many days it will take for them to drink 1 barrel of water together, and they drink 1/4 of a gallon every day, we do
(1) / (1/4) = 1 * (4/1) = 4 days
It will take 4 days for John and Mary to drink 1 barrel together.
Hope this helps!
49 divided by 7 is 7.
The answer is 7 flowers in each vase.
Answer:
The number of cows and calves Mitchel can transport is determined by the inequity 
Step-by-step explanation:
Let 
be the number of goats, and 
be the number of cows. If Mitchel's livestock trailer can only hold maximum of 5000 pounds. then we have the inequality
<em>(this says that the weight of the goats and the calves cannot exceed 500 pounds.) </em>
Therefore, this inequality determines the number of goats and calves Mitchel can take in a single trip.
