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AfilCa [17]
2 years ago
9

There are 49 flowers to split evenly between 7 vases. How many flowers go in each vase?

Mathematics
2 answers:
GuDViN [60]2 years ago
8 0

Answer:

Hi!

The correct answer is 7 flowers in each vase.

Step-by-step explanation:

Suppose you have 7 rounds where in each round you put one flower in each vase.

1rst round: 1 flower in each vase. 7 flowers splitted.

2nd round: 2 flowers in each vase. 14 flowers splitted.

3rd round: 3 flowers in each vase. 21 flowers splitted.

4th round: 4 flowers in each vase. 28 flowers splitted.

5th round: 5 flowers in each vase.  35 flowers splitted.

6th round: 6 flowers in each vase.  42 flowers splitted.

7th round: 7 flowers in each vase.  49 flowers splitted.

It means that you can do divide 49 flowers into 7 vases.

  • 49/7 = 7
dexar [7]2 years ago
3 0
49 divided by 7 is 7. 

The answer is 7 flowers in each vase.
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Answer:

B, D, and E

Step-by-step explanation:

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There are 220 students in Year 7. 15% cycle to school. 60% are driven to school. The rest walk to school. (a) How many students
Paha777 [63]

Answer:

cycle=33 students, driven=132 students, walk=55 students

Step-by-step explanation:

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7 0
2 years ago
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A company has two warehouses that are 360 miles apart. A truck leaves Warehouse A and heads towards Warehouse B traveling at 45
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5 0
2 years ago
In ΔABC, AD and BE are the angle bisectors of ∠A and ∠B and DE ║ AB . If m∠ADE is with 34° smaller than m∠CAB, find the measures
Charra [1.4K]

Answer:

34°

Step-by-step explanation:

If m∠ADE is with 34° smaller than m∠CAB, then denote

m∠ADE=x°,

m∠CAB=(x+34)°.

Since  DE ║ AB, then

m∠ADE=m∠DAB=x°.

AD is angle A bisector, then

m∠EAD=m∠DAB=x°.

Thus,

m∠CAB=m∠CAD+m∠DAB=(x+x)°=2x°.

On the other hand,

m∠CAB=(x+34)°,

then

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7 0
2 years ago
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yaroslaw [1]

This question is based on least common multiple method.

As given in the question,

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So we have been asked what is the minimum number of aunts Sana have.

As we have been given that the number of aunts and uncles is equal so to find the minimum number of aunts we will apply the least common multiple method.

So we get LCM of 5,10 as 10

Hence there are minimum 10 aunts.


3 0
2 years ago
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