Mitchel owns a livestock trailer that can hold a maximum of 5,000 pounds. The average weight of each goat is 90 pounds, and the
average weight of each calf is 360 pounds. Mitchel would like to know how many goats and calves he can transport in a single trip.
1 answer:
Answer:
The number of cows and calves Mitchel can transport is determined by the inequity
Step-by-step explanation:
Let be the number of goats, and
be the number of cows. If Mitchel's livestock trailer can only hold maximum of 5000 pounds. then we have the inequality
<em>(this says that the weight of the goats and the calves cannot exceed 500 pounds.) </em>
Therefore, this inequality determines the number of goats and calves Mitchel can take in a single trip.
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Answer:
<h3>AC=96 units.</h3>Step-by-step explanation:
We are given a parallelogram ABCD with diagonals AC and BD intersect at point E.
, and CE=6x .
<em>Note: The diagonals of a parallelogram intersects at mid-point.</em>
Therefore, AE = EC.
Plugging expressions for AE and EC, we get
Subtracting 6x from both sides, we get
Factoriong quadratic by product sum rule.
We need to find the factors of -16 that add upto -6.
-16 has factors -8 and +2 that add upto -6.
Therefore, factor of quadratic is (x-8)(x+2)=0
Setting each factor equal to 0 and solve for x.
x-8=0 => x=8
x+2=0 => x=-2.
We can't take x=-2 as it's a negative number.
Therefore, plugging x=8 in EC =6x, we get
EC = 6(8) = 48.
<h3>AC = AE + EC = 48+48 =96 units.</h3>