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tatyana61 [14]
1 year ago
11

Anita had $400 in her savings account when she went to college. Her parents will add $200 to her account each month. Miguel had

$25 in his savings account. His parents will double the amount in his account each month. If Anita and Miguel do not take any money from their accounts, whose account will grow faster? Explain why.
Mathematics
1 answer:
lesantik [10]1 year ago
5 0
At first, Anita looks like her account would grow faster. By month 4, shes at $1,200 while Miguel is at $400. However, Anita is only getting $200 a month. While Miguel gets double of whatever amount he has in his bank account. By month 10, Anita is at $2,400 while Miguel has $25,600. That is a $23,200 difference. So Miguel's bank account will grow faster than Anita.
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C

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hmu also What is the sum and classification of Two-fifths + StartRoot 88 EndRoot? 9.78083151..., irrational 9.78083151..., ratio
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Answer:

9.78083151 irrational

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Step-by-step explanation:

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A doctor is measuring the average height of male students at a large college. The doctor measures the heights, in inches, of a s
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Answer:

For this case the  95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:

b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.

Step-by-step explanation:

Notation

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=40-1=39

For this case the  95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:

b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.

3 0
2 years ago
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