Answer:
The probability that the proportion of passed keypads is between 0.72 and 0.80 is 0.6677.
Step-by-step explanation:
According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
The mean of this sampling distribution of sample proportion is:

The standard deviation of this sampling distribution of sample proportion is:

Let <em>p</em> = the proportion of keypads that pass inspection at a cell phone assembly plant.
The probability that a randomly selected cell phone keypad passes the inspection is, <em>p</em> = 0.77.
A random sample of <em>n</em> = 111 keypads is analyzed.
Then the sampling distribution of
is:

Compute the probability that the proportion of passed keypads is between 0.72 and 0.80 as follows:


Thus, the probability that the proportion of passed keypads is between 0.72 and 0.80 is 0.6677.
Slope intercept form is y=mx+b
So we're solving the equation in the question for y.
First, we subtract 6x from both sides to get
2y<-46-6x. Then we divide both sides by 2 to get y alone.
Then the answer will be y<-46÷2 -6x÷2
FInal answer = y< -23-3x or y<-3x-23
Step-by-step explanation:
dA/dt = 6 − 0.02A
dA/dt = -0.02 (A − 300)
Separate the variables.
dA / (A − 300) = -0.02 dt
Integrate.
ln(A − 300) = -0.02t + C
Solve for A.
A − 300 = Ce^(-0.02t)
A = 300 + Ce^(-0.02t)
Use initial condition to find C.
50 = 300 + Ce^(-0.02 × 10)
50 = 300 + Ce^(-0.2)
-250 = Ce^(-0.2)
C = -250e^(0.2)
A = 300 − 250e^(0.2) e^(-0.02t)
A = 300 − 250e^(0.2 − 0.02t)
Total weight = 50 lb
x = number of 3-lb weights
y = number of 10-lb weights
weight of 3-lb weights = 3x
weight of 10-lb weights = 10y
total weight = 3x + 10y
equation
3x + 10y = 50