1/2 because 5/9 is equivalent to 10/18. Half of 18 is 9 and 10 is close to 9 so the nearest benchmark fraction you should round to is 1/2. Hope this helps you!
This is an isosceles right triangle (AB = BC & ∠ B=90° - Given)
Then the angles at the base are equal and ∠ CAB = ∠ ACB = 45°
Theorem: Segment DE, joining the midpoints of 2 sides is:
1st) parallel to the 3rd side and
2nd) equal to half the measurement of the 3rd side
So if the 3rd side (hypotenuse) = 9 units, DE = 9/2 = 4.5 units
9514 1404 393
Answer:
∛(2500π)√37 m² ≈ 120.911 m²
Step-by-step explanation:
If the height is 3 times the diameter, it is 6 times the radius. Then the volume is ...
V = 1/3πr²h
V = 1/3πr²(6r) = 2πr³
For a volume of 100 m³, the radius is ...
100 m³ = 2πr³
r = ∛(50/π) m
The lateral area of the cone is computed from the slant height. For this cone, the slant height is found using the Pythagorean theorem:
s² = r² +(6r)² = 37r²
s = r√37
Then the lateral area is ...
LA = πrs
LA = π(∛(50/π) m)(∛(50/π) m)√37
LA = ∛(2500π)√37 m² ≈ 120.911 m²
Answer:
mBCD = 28°
Step-by-step explanation:
The angle mBFD inscribes the arc mBD, so we have that:
mBFD = mBD/2
76 = mBD/2
mBD = 152°
The angle mBOD is a central angle related to the arc mBD, so we have that:
mBOD = mBD = 152°
In the quadrilateral BODC, the sum of internal angles needs to be equal to 360° (property of all convex quadrilaterals). The angles mCBO and mCDO are right angles, because EDC and ABC are tangents to the circle.
So, we have that:
mBOD + mCDO + mBCD + mCBO = 360
152 + 90 + mBCD + 90 = 360
mBCD = 360 - 90 - 90 - 152
mBCD = 28°
Answer:
Step-by-step explanation:
Let the outside temperature be 
degree.
So, when 
degree, number of members, 
Now, for every degree rise in temperature, 10 members gets added.
So, when the temperature is degrees, rise in temperature is 
degrees.
Therefore,
For degrees rise, number of members added = 
Hence, total number of members added as a function of temperature is given as the sum of members at 
degrees and for degrees rise. This gives,
