Question

Agent Hunt transferred classified files from the CIA mainframe onto his flash drive. The drive had some files on it before the transfer, and the transfer happened at a rate of 4.44.44, point, 4 megabytes per second. After 323232 seconds, there were 384384384 megabytes on the drive. The drive had a maximum capacity of 100010001000 megabytes.
How full was the drive when the transfer began?

Answer 1

Ok with your new values i can solve this questions for you.

the hard drive was 24.32% full when the transfer began. 

4.4 x 32 = 140.8

384 - 140.8 = 243.2

243.2 divided by 1000 = 0.2432 

move the decimal 2 places to the right to create a percentage and you now have your answer of 24.32%

Answer 2

Answer:   The drive was 24.32% full when the transfer began.

 

Step-by-step explanation:

Given: The rate of transferring file = 4.44 megabytes per second.

After 32 seconds, the amount of data on the drive = 384 megabytes  

The amount of transferred data = $32\times4.4=140.8$ megabytes  

Therefore, the amount of data in the drive at the beginning is given by :-

$\text{Beginning amount=Amount after 32 seconds -Amount transferred}\\\\\Rightarrrow\ \text{Beginning amount=}384-140.8=243.2$

The drive had a maximum capacity of 1000 megabytes.

$\frac{243.2}{1000}\times100=24.32\%$

Hence, the drive was 24.32% full when the transfer began.