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photoshop1234 [79]

2 years ago

15

Explain why you cannot find the intersection points of the two lines shown below. Give both an algebraic reason and a graphical

reason. y=4x+1 and y= 4x+10

1 answer:

Art [367]2 years ago

5 0

Answer:

$m_1 = m_2 = 4$

Step-by-step explanation:

Given

$y = 4x + 1$

$y = 4x + 10$

Required

Show that these two lines have no point of intersection

The general equation of a line is

$y = mx + b$

Where m represents slope

In $y = 4x + 1$

$m = 4$

Similarly; in $y = 4x + 10$

$m = 4$

Since the slope of both lines are equal;

$m_1 = m_2 = 4$

<em>This implies that the lines are parallel and parallel lines have no point of intersection</em>

<em></em>

<em>See Attachment for Graph</em>

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HELPP ASAP NEEDED MATH

trapecia [35]

Answer:

992

Step-by-step explanation:

Divide 1000 by 26.

The answer is 38 and some left over. We don't care what the leftover is because it is nearly 0.5 and that means 13 people were left over.

Take the integer value (38) and multiply it by 26. You get 988.

You want there to be 4 left over. 4 + 988 = 992. That's one way of doing the problem.

6 0

2 years ago

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Triangle S R Q is shown. Angle S R Q is a right angle. An altitude is drawn from point R to point T on side S Q to form a right

Jet001 [13]

Answer:

Option B.

Step-by-step explanation:

It is given that ΔSRQ is a right angle triangle, ∠SRQ is right angle.

RT is altitude on side SQ, ST=9, TQ=16 and SR=x.

In ΔSRQ and ΔSTR,

$m\angle S=m\angle S$ (Reflexive property)

$m\angle R=m\angle T$ (Right angle)

By AA property of similarity,

$\triangle SRQ\sim \triangle STR$

Corresponding parts of similar triangles are proportional.

$\dfrac{SR}{SQ}=\dfrac{ST}{SR}$

Substitute the given values.

$\dfrac{x}{9+16}=\dfrac{9}{x}$

$\dfrac{x}{25}=\dfrac{9}{x}$

On cross multiplication we get

$x^2=25\times 9$

$x^2=225$

Taking square root on both sides.

$x=\sqrt{225}$

$x=15$

The value of x is 15. Therefore, the correct option is B.

7 0

2 years ago

Read 2 more answers

A child wanders slowly down a circular staircase from the top of a tower. With x,y,zx,y,z in feet and the origin at the base of

babymother [125]

Answer:

a) The tower is 90 feet tall

b) She reaches the bottom at t = 18 minutes.

c) Her speed at time t is 5 \sqrt[]{5} ft/minute

d) Her acceleration at time t is 10 ft/minute^2

Step-by-step explanation:

Consider the path described by the child as going down the tower to have the following parametrization $\gamma(t) = (10\cos t, 10 \sin t, 90-5t)$

a) Assuming that the child is at the top of the tower when she starts going down, we have that at the initial time (t=0) we will have the value of the height of the tower. That is z = 90-5*0 = 90 ft.

b) The child reaches the bottom as soon as z =0. We want to find the value of t that does that. Then we have 0 = 90-5t, which gives us t = 18 minutes.

c) Given the parametrization we are given, the velocity of the child at time t is given by $\frac{d\gamma}{dt}= (\frac{d}{dt}(10\cos t), \frac{d}{dt} (10 \sin t ), \frac{d}{dt}(90-5t)) = (-10 \sin t, 10 \cos t, -5)$ . The speed is defined as the norm of the velocity vector,

so, the speed at time t is given by $v = \sqrt[]{(-10 \sin t)^2+(10 \cos t)^2+(-5)^2} = \sqrt[]{100(\sin^2 t + \cos^2 t)+25} = \sqrt[]{125}= 5 \sqrt[]{5}$

d) ON the same fashion we want to know the norm of the second derivative of $\gamma$ .

We have that $\gamma ^{''}(t) =(-10\cost t, -10 \sin t , 0)$ so the acceleration is given by $\sqrt[]{100(\cos^2 t+ \sin^2 t )} = 10$

6 0

1 year ago

Round to the nearest hundred thousand <br> 89, 659

victus00 [196]

Answer:

The nearest hundred thousand of the provided number is 100,000.

Step-by-step explanation:

Consider the provided number 89, 659

According to place value.

Hundred Th. Ten Th. Thousands hundreds Tens Ones

100,000 10,000 1000 100 10 1

We need to round it to the nearest hundred thousand.

The provided number can be written as 089,659

The digit at the hundred thousand place is 0.

The rule of rounding a number is:

If 0, 1, 2, 3, or 4 follow the number, then no need to change the rounding digit.

If 5, 6, 7, 8, or 9 follow the number, then rounding digit rounds up by one number.

Here, the number at the ten thousands place is 8, so to round up the number increase the digit of hundred thousand place by 1.

The digit at the hundred thousand place is 0 so increase it by 1.

Thus, the number can be rounded to the nearest hundred thousand is shown as:

100,000

The nearest hundred thousand of the provided number is 100,000.

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1 year ago

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Andrew invested $20,000 in mutual funds and received a sum of $35,000 at the end of the investment period. Calculate the ROI.

mario62 [17]

Answer: $15,000

As $35,000-$20,000=$15,000.

That's basically the profit he had made, or the return on his investment (ROI).

As he already had $20,000, he had "only" made $15,000.

5 0

2 years ago