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Lilit [14]
2 years ago
15

The grade point average (GPA) of the students at Lakeview High School is normally distributed with a mean of 3.1 and a standard

deviation of 0.3. If there are 1800 students enrolled at the school, approximately how many have a GPA between 2.5 and 3.7?
Mathematics
1 answer:
Morgarella [4.7K]2 years ago
4 0
Approximately 1718 have a score within that range.

We calculate the z-score for each end of this spectrum:

z = (X-μ)/σ = (2.5-3.1)/0.3 = -0.6/0.3 = -2

Using a z-table (http://www.z-table.com) we see that the area to the left of, less than, this z-score is 0.0228.

For the upper end:
z = (3.7-3.1)/0.3 = 0.6/0.3 = 2

Using a z-table, we see that the area to the left of, less than, this z-score is 0.9772.

The probability between these is given by subtracting these:
0.9772 - 0.0228 = 0.9544.

This means the proportion of people that should fall between these is 0.9544:
0.9544*1800 = 1717.92 ≈ 1718
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Anwser: C
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4 0
1 year ago
The selling price of a chair is N14 000. The trader gives a 25% discount for cash. What is the cash price?
True [87]

Answer:N10500

Step-by-step explanation:

10%of 14000=1400

20%=1400x2=2800

5%=1400 divided by 2=700

25%=2800+700=3500

14000-3500=10500

hope this helps

5 0
2 years ago
If e = 9 cm and f = 40 cm, what is the length of g?
rewona [7]

(9,40,41) is a Pythagorean Triple, farther down the list than teachers usually venture.

Answer: D. 41 cm

There's a subset of Pythagorean Triples where the long leg is one less than the hypotenuse,

a^2+b^2 = (b+1)^2

a^2 + b^2 = b^2 + 2b +1

a^2=2b+1

So we get one for every odd number, since the square of an odd number is odd and the square of an even number is even.

b = (a^2 - 1)/2

a=3, b=(3^2-1)/2=4, c=b+1=5

a=5, b=(5^2-1)/2 =12, c = 13

a=7, b=24, c=25

a=9, b=40, c=41

a=11, b=60, c=61

a=13, b=84, c=85

It's good to be able to recognize Pythagorean Triples when we see them.  

Otherwise we'd have to work the calculator:

√(9² + 40²) = √1681 = 41

8 0
2 years ago
There are two misshapen coins in a box; their probabilities for landing on heads when they are flipped are, respectively, .4 and
Leokris [45]

Answer:

E(X) = 6.0706

Step-by-step explanation:

1) Define notation

X = random variable who represents the number of heads in the 10 first tosses

Y = random variable who represents the number of heads in range within toss number 4 to toss number 10

And we can define the following events

a= The first coin has been selected

b= The second coin has been selected

c= represent that we have 2 Heads within the first two tosses

2) Formulas to apply

We need to find E(X|c) = ?

If we use the total law of probability we can find E(Y)

E(Y) = E(Y|a) P(a|c) + E(Y|b)P(b|c) ....(1)

Finding P(a|c) and using the Bayes rule we have:

P(a|c) = P(c|a) P(a) / P(c) ...(2)

Replacing P(c) using the total law of probability:

P(a|c) = [P(c|a) P(a)] /[P(c|a) P(a) + P(c|b) P(b)] ... (3)

We can find the probabilities required

P(a) = P(b) = 0.5

P(c|a) = (3C2) (0.4^2) (0.6) = 0.288

P(c|b) = (3C2)(0.7^2) (0.3) = 0.441

Replacing the values into P(a|c) we got

P(a|c) = (0.288 x 0.5) /(0.288x 0.5 + 0.441x0.5) = 0.144/ 0.3645 = 0.39506

Since P(a|c) + P(b|c) = 1. With this we can find P(b|c) = 1 - P(a|c) = 1-0.39506 = 0.60494

After this we can find the expected values

E(Y|a) = 7x 0.4 = 2.8

E(Y|b) = 7x 0.7 = 4.9

Finally replacing the values into equation (1) we got

E(Y|c) = 2.8x 0.39506 + 4.9x0.60494 = 4.0706

And finally :

E(X|c) = 2+ E(Y|c) = 2+ 4.0706 = 6.0706

6 0
2 years ago
At a display booth at an amusement park, every visitor gets a gift bag. Some
kotegsom [21]

The bag will often contain all three items every 70 bags ⇒ answer C

Step-by-step explanation:

At a display booth at an amusement park, every visitor gets a gift bag

according to these information:

1. Hat Every 2nd visitor

2. T-shirt Every 7th visitor

3. Backpack Every 10th visitor

We need to know how often a bag will contain all three items

To solve this problem you must find a number divisible by 2, 7, and 10

To find that number start with the multiples of the largest one and

check them with the other two numbers

∵ The largest number is 10

∵ The multiples of 10 are 10 , 20 , 30 , 40 , 50 , 60 , 70 , 80 , .......

- Look for the first multiple of 10 is divisible by 7

∵ 70 is the first multiple of 10 divisible by 7

∵ 70 is divisible by 2 because its even number

∴ 70 is the smallest number divisible by 2, 7 and 10

The bag will often contain all three items every 70 bags

Learn more:

You can learn more about numbers in brainly.com/question/537998

#LearnwithBrainly

4 0
2 years ago
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