Becky is writing a coordinate proof to show that the diagonals of a parallelogram bisect each other. She starts by assigning coo
rdinates as given.
A parallelogram graphed on a coordinate plane. The parallelogram is labeled A B C D. The coordinates of vertex A are 0 comma 0. The coordinates of vertex B a comma 0. The coordinates of vertex C are not labeled. The coordinates of vertex D are b comma c. Diagonals A C and B D intersect at point E whose coordinates are not labeled.
Drag and drop the correct answer into each box to complete the proof.
The coordinates of point C are (Response area, c).
The coordinates of the midpoint of diagonal AC¯¯¯¯¯ are (a+b2, c2) .
The coordinates of the midpoint of diagonal BD¯¯¯¯¯ are (Response area, c2).
AC¯¯¯¯¯ and BD¯¯¯¯¯ intersect at point E with coordinates (a+b2,Response area)..
By the definition of midpoint, AE¯¯¯¯¯≅Response area and Response area≅DE¯¯¯¯¯.
Therefore, diagonals AC¯¯¯¯¯ and BD¯¯¯¯¯ bisect each other.
Give actual answer will give brainliest
A parallelogram graphed on a coordinate plane. The parallelogram is labeled A B C D. The coordinates of vertex A are 0 comma 0. The coordinates of vertex B a comma 0. The coordinates of vertex C are not labeled. The coordinates of vertex D are b comma c. Diagonals A C and B D intersect at point E whose coordinates are not labeled.
Drag and drop the correct answer into each box to complete the proof.
The coordinates of point C are (Response area, c).
The coordinates of the midpoint of diagonal AC¯¯¯¯¯ are (a+b2, c2) .
The coordinates of the midpoint of diagonal BD¯¯¯¯¯ are (Response area, c2).
AC¯¯¯¯¯ and BD¯¯¯¯¯ intersect at point E with coordinates (a+b2,Response area)..
By the definition of midpoint, AE¯¯¯¯¯≅Response area and Response area≅DE¯¯¯¯¯.
Therefore, diagonals AC¯¯¯¯¯ and BD¯¯¯¯¯ bisect each other.
Give actual answer will give brainliest
2 answers:
You might be interested in
Answer:
a) 0.05
b) 0.9826
c) 0.000039308
Step-by-step explanation:
a)
b) For two minutes, the mean is doubled, hence it is 6. In order to calculate the probability of al least two calls arriving, we calculate first the probability of the complementary event: At most 1 call will arrive. For that probability, we need to sum the probabilities of 0 and 1.
Hence,
c) For five minutes the mean is 15. We need to sum the probabilities of 0, 1 and 2.
As a result,
Practically 0