Becky is writing a coordinate proof to show that the diagonals of a parallelogram bisect each other. She starts by assigning coo
rdinates as given.
A parallelogram graphed on a coordinate plane. The parallelogram is labeled A B C D. The coordinates of vertex A are 0 comma 0. The coordinates of vertex B a comma 0. The coordinates of vertex C are not labeled. The coordinates of vertex D are b comma c. Diagonals A C and B D intersect at point E whose coordinates are not labeled.
Drag and drop the correct answer into each box to complete the proof.
The coordinates of point C are (Response area, c).
The coordinates of the midpoint of diagonal AC¯¯¯¯¯ are (a+b2, c2) .
The coordinates of the midpoint of diagonal BD¯¯¯¯¯ are (Response area, c2).
AC¯¯¯¯¯ and BD¯¯¯¯¯ intersect at point E with coordinates (a+b2,Response area)..
By the definition of midpoint, AE¯¯¯¯¯≅Response area and Response area≅DE¯¯¯¯¯.
Therefore, diagonals AC¯¯¯¯¯ and BD¯¯¯¯¯ bisect each other.
Give actual answer will give brainliest
A parallelogram graphed on a coordinate plane. The parallelogram is labeled A B C D. The coordinates of vertex A are 0 comma 0. The coordinates of vertex B a comma 0. The coordinates of vertex C are not labeled. The coordinates of vertex D are b comma c. Diagonals A C and B D intersect at point E whose coordinates are not labeled.
Drag and drop the correct answer into each box to complete the proof.
The coordinates of point C are (Response area, c).
The coordinates of the midpoint of diagonal AC¯¯¯¯¯ are (a+b2, c2) .
The coordinates of the midpoint of diagonal BD¯¯¯¯¯ are (Response area, c2).
AC¯¯¯¯¯ and BD¯¯¯¯¯ intersect at point E with coordinates (a+b2,Response area)..
By the definition of midpoint, AE¯¯¯¯¯≅Response area and Response area≅DE¯¯¯¯¯.
Therefore, diagonals AC¯¯¯¯¯ and BD¯¯¯¯¯ bisect each other.
Give actual answer will give brainliest
2 answers:
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Answer:
The degrees of freedom are given by:
The p value for this case is given by:
For this case since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 200 F.
Step-by-step explanation:
Information given
data: 202.2 203.4 200.5 202.5 206.3 198.0 203.7 200.8 201.3 199.0
We can calculate the sample mean and deviation with the following formulas:
represent the sample mean
represent the sample standard deviation
sample size
represent the value that we want to test
represent the significance level for the hypothesis test.
t would represent the statistic
represent the p value for the test
Hypothesis to test
We want to determine if the true mean is equal to 200, the system of hypothesis are :
Null hypothesis:
Alternative hypothesis:
The statistic for this case is given by:
(1)
The statistic is given by:
The degrees of freedom are given by:
The p value for this case is given by:
For this case since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 200 F.