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Travka [436]
2 years ago
15

You are on a business trip in Great Britain. Great Britain uses the pound for currency. The exchange rate is 1 British Pound is

equivalent to $1.46. If you exchange $100 for British pounds, how many pounds will you receive?
Mathematics
2 answers:
artcher [175]2 years ago
8 0
If the exchange rate is $1.46 and you are exchanging $100, you will receive 146 pounds.
tatiyna2 years ago
6 0

Answer:

You will get 68.493 British Pounds.

Step-by-step explanation:

You are on a business trip in Great Britain. Great Britain uses the pound for currency.

The exchange rate is 1 British Pound is equivalent to $1.46.

Now, you are exchanging $100 for British pounds, so it will be \frac{100}{1.46}

$100 x (1 Pound/$1.46)

= 68.493 British Pounds.

Therefore, you will get 68.493 British Pounds.

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Which of the following represents "The product of the abscissa and ordinate is ten"?
Ainat [17]
Hello,
if x represents the abscissa
and y the ordinate then
the product is x*y
Answer A

6 0
2 years ago
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Which expression is equivalent to StartFraction (3 m Superscript negative 2 Baseline n) Superscript negative 3 Baseline Over 6 m
Dovator [93]

Option a: \frac{m^{5} }{162n} is the equivalent expression.

Explanation:

The expression is \frac{(3m^{-2} n)^{-3}}{6mn^{-2} } where m\neq 0, n\neq 0

Let us simplify the expression, to determine which expression is equivalent from the four options.

Multiplying the powers, we get,

\frac{3^{-3}m^{6} n^{-3}}{6mn^{-2} }

Cancelling the like terms, we have,

\frac{3^{-3}m^{5} n^{-1}}{6 }

This equation can also be written as,

\frac{m^{5}}{3^{3}6 n^{1} }

Multiplying the terms in denominator, we have,

\frac{m^{5} }{162n}

Thus, the expression which is equivalent to \frac{(3m^{-2} n)^{-3}}{6mn^{-2} } is \frac{m^{5} }{162n}

Hence, Option a is the correct answer.

8 0
2 years ago
Read 2 more answers
The data represented by the graph is normally distributed and adheres to the 68-95-99.7 rule. The standard deviation of this dat
KiRa [710]
Hello,
Please, see the attached files.
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4 0
2 years ago
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Emma was about to finish grocery shopping when she noticed that cans of soup were on sale. Her total bill for groceries would be
Alinara [238K]

Answer:

3rd option: B(C)= 1.79C +86.03

Step-by-step explanation:

Total bill

= cost of cans(number of cans) +cost of other groceries

Let the cost of other groceries be G, and the cost of cans be X.

Given that number of cans= C,

Total bill= XC +G

If 2 cans were purchased,

2X+G= 89.61 -----(1)

If 5 cans were purchased,

5X +G= 94.98 -----(2)

(2) -(1):

(5X +G) -(2X +G)= 94.98 -89.61

5X +G -2x -G= 5.37

3X= 5.37

X= 5.37 ÷3 <em>(</em><em>÷</em><em>3</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>

X= 1.79

Subst. X= 1.79 into (1):

2(1.79) +G= 89.61

3.58 +G= 89.61

G= 89.61 -3.58 <em>(</em><em>-3.58</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>

G= 86.03 <em>(</em><em>simplify</em><em>)</em>

Total bill

= XC +G

= 1.79C +86.03

Thus, the function is B(C)= 1.79C +86.03.

3 0
2 years ago
Which classification best describes the following system of equations? 3x+6y-12z=36 x=2y-4z=12 4x+8y-16z=48 inconsistent and dep
Viktor [21]

<u>Answer:</u>

Consistent and dependent

<u>Step-by-step explanation:</u>

We are given the following equation:

1. 3x+6y-12z=36

2. x+2y-4z=12

3. 4x+8y-16z=48

For equation 1 and 3, if we take out the common factor (3 and 4 respectively) out of it then we are left with x+2y-4z=12 which is the same as the equation number 2.

There is at least one set of the values for the unknowns that satisfies every equation in the system and since there is one solution for each of these equations, this system of equations is consistent and dependent.

6 0
2 years ago
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