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masya89 [10]
2 years ago
9

The graph shows the relationship between the number of strawberries eaten and the approximate number of calories consumed. Which

statement is true?
Each strawberry contains 4 calories.
Each strawberry contains 3 calories.
Twenty-four strawberries contain 6 calories.
Four strawberries contain 15 calories.

Mathematics
2 answers:
Ulleksa [173]2 years ago
7 0

Answer:

its 4 calories, A

Step-by-step explanation:

i just got it right on edge

Mandarinka [93]2 years ago
5 0

9514 1404 393

Answer:

  Each strawberry contains 4 calories

Step-by-step explanation:

The graph crosses the vertical line for 1 strawberry above the intersection with the horizontal line for 3, so there are more than 3 calories in 1 strawberry. The graph crosses "strawberries = 1" at about "calories = 4", matching the first statement.

Similarly, the graph crosses the vertical line for 4 strawberries above the horizontal line for 15 calories. An estimate of 16 calories for 4 strawberries is consistent with the first statement (4 calories in each strawberry).

The point (6, 24) is on the graph, but it means (6 strawberries, 24 calories), not the other way around.

The appropriate choice is ...

  Each strawberry contains 4 calories

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Answer:the answer to this question is 4

Step-by-step explanation: becuse idk im just trying to gain points sorry

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What two products would you add to find 713​x48
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Answer:

  40·713 and 8·713

Step-by-step explanation:

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2 years ago
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01:57:09 In a city, the distance between the library and the police station is 3 miles less than twice the distance between the
tester [92]

Answer:

Distance between the police station and the fire station be 4 miles

Step-by-step explanation:

Let distance between the police station and the fire station be x miles.

The distance between the library and the police station is 3 miles less than twice the distance between the police station and the fire station.

Distance between the library and the police station =2x-3

Also, distance between the library and the police station is 5 miles.

2x-3=5\\2x=3+5\\2x=8\\x=\frac{8}{2}\\ x=4\,\,miles

8 0
2 years ago
In professional basketball games during 2009-2010, when Kobe Bryant of the Los Angeles Lakers shot a pair of free throws, 8 time
ziro4ka [17]

Answer:

Is plausible that the successive throws are independent

Step-by-step explanation:

1) Table with info given

The observed values are given by the following table

__________________________________________________

First shot          Made          Second shot missed           Total

__________________________________________________

Made                  152                       33                                185

Missed                37                         8                                  45

__________________________________________________

Total                    189                       41                                230

2) Calculations and test

We are interested on check independence and for this we need to conduct a chi square test, the next step would be find the expected value:

Null hypothesis: Independence between two successive free throws

Alternative hypothesis: No Independence between two successive free throws

_____________________________________________________

First shot                    Made                                    Second shot missed

_____________________________________________________

Made                  189(185)/230=152.0217                41(185)/230=32.9783

Missed                189(45)/230=36.9783                  41(45)/230=8.0217

_____________________________________________________

On this case all the expected values are higher than 5 and the sample size 230 is enough to apply the chi squared test.

3) Calculate the chi square statistic

The statistic for this case is given by:

\chi_{cal}^2 =\sum \frac{(O_i -E_i)}{E_i}

Where O represent the observed values and E the expected values. Replacing the values that we got we have this

\chi_{cal}^2 =\frac{(152-152.0217)^2}{152.0217}+\frac{(33-32.9783)^2}{32.9783}+\frac{(37-36.9783)^2}{36.9783}+\frac{(8-8.0217)^2}{8.0217}=0.000003098+0.00001428+0.00001273+0.0.00005870=0.00008881

Now with the calculated value we can find the degrees of freedom

df=(r-1)(c-1)=(2-1)(2-1)=1 on this case r means the number of rows and c the number of columns.

Now we can calculate the p value

p_v =P(\chi^2 >0.00008881)=0.9925

On this case the pvalue is a very large value and that indicates that we can fail to reject the null hypothesis of independence. So is plausible that the successive throws are independent.

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