<span>Amanda has 26 nickels and dimes.
We shall call nickels x and dimes y.
We can write the following equations:
x = 3y -2 or -x +3y = 2
x + y = 26
We can cancel out the x to give 4y = 28 or y = 7
If there are 26 coins in total and 7 of them are dimes then there must be 19 nickels.
The number of nickels (19) is two fewer than three times the number of dimes ( 3(7) - 2 = 19).</span>
Answer:
Step-by-step explanation:
Given that a teacher gives a test to a large group of students. The results are closely approximated by a normal curve
mu =74 and sigma =8
A grade starts from 100-8 = 92nd percentile
Z score for 92nd percentile = 1.405
X score = 74+8(1.405) = 85.24
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B cut off is to next 16%
Hence C would start for scores below 100-(8+16) = 76%
76th percentile = 0.705*8+74 =79.64
<span>4(2p+4q+6)
You need to multiply 4 by each variable in the parentheses.
(4*2p) + (4*4q) + (4*6)
8p + 16q + 24 is the answer.</span>
Answer:
Step-by-step explanation:
a) For a prime numbers we have array with 2 rectangulars R1: a=1 and b=prime number; R2: a=prime number and b=1. Both has the same are, that prime number.
b) For a composite number which are not square number we have rectanular array with even numbers of ractangulars. For example, number 6.
R1: a=1,b=6; R2: a=2,b=3; R3: a=3, b=2; R4: a=6,b=1. Each rectangular has the same area, 6.
c) The square number we alway have te odd number of rectanulars, because of the square a=x,b=x can not be simetric. For example 16.
R1: a=1,b=16; R2: a=2 , b=8; R3: a=4,b=4; R4: a=8, b=2; R5:a=16,b=1.Each rectangular has the same area, 16.
If two triangles are congruent, then they have equal corresponding angles and also the sides.
Therefore, if GHI is congruent to LMN, then GH =LM, HI=MN and GI=LN, and also angle G=angle L, Angle H=angle M, while angle I = angle N, therefore the correct answers is a) ∠M= ∠H, c) ∠L=∠G. and e)IH=NM.
