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2 years ago

Assume that triangle GHI is congruent to LMN. Which of the following congruence statement are correct? check all that apply

Mathematics

2 answers:

Vsevolod [243]2 years ago

6 0

Answer.

GH = LM

<N = <I

<M = <H

IH = NM

Just got it wrong on APEX

Airida [17]2 years ago

5 0

If two triangles are congruent, then they have equal corresponding angles and also the sides.
Therefore, if GHI is congruent to LMN, then GH =LM, HI=MN and GI=LN, and also angle G=angle L, Angle H=angle M, while angle I = angle N, therefore the correct answers is a) ∠M= ∠H, c) ∠L=∠G. and e)IH=NM.

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PLEASE HELP THANK YOUUUU Your group has $120 available for the banquet. Any other costs must be covered from selling tickets for

Keith_Richards [23]

Answer:

The cost C, of hosting the banquet with the services of Caterer One is;

C = $ 45·n

The cost C, of hosting the banquet with the services of Caterer Two is;

C = $250 + $ 28·n

The cost C, of hosting the banquet with the services of Caterer Three is;

C = $500 + $ 20·n

Step-by-step explanation:

The information includes;

The amount available to the group for the banquet = $120

The number of people attending the banquet = n

The cost incurred in hosting the banquet = C

The major costs in hosting the banquet are hall rental and caterer

The cost per caterer are as follows;

Caterer One

The cost per person including the hall = $45

Therefore, the cost incurred, C, in hosting the banquet using caterer one is equal;

C = n × $45 = $ 45·n

Caterer Two

The hall rental = $250

The cost per person = $28

Therefore, the cost incurred, C, in hosting the banquet using caterer two is equal;

C = $250 + n × $28 = $250 + $ 28·n

Caterer Three

The hall rental = $500

The cost per person = $20

Therefore, the cost incurred, C, in hosting the banquet using caterer three is equal;

C = $500 + n × $20 = $500 + $ 20·n.

5 0

1 year ago

erica is making necklaces and bracelets to se at the craft show. it takes her 3 hours to make a necklace and 2 hours to make a b

bagirrra123 [75]

Answer:

Erica should make at least 10 necklaces and 15 bracelets to maximize her profit of P = (18 x + 15 y)

Step-by-step explanation:

Let the number of necklaces made = x

Let the number of bracelets made by Erica = y

Now, the time taken to make each necklace = 3 hrs

⇒The time taken to make x necklaces = x times 3 hours = 3x

Also, the time taken to make each bracelet = 2 hrs

⇒The time taken to make y necklaces = y times 2 hours = 2y

So, total time taken to make x necklace and y bracelets = 3x + 2y

Now selling cost of 1 necklace = $18

Also, selling cost of 1 bracelet = $15

So, total selling price of x necklace and y bracelets = 18 x + 15 y

So according to the question:

x + y = 25 ..... (1)

3x + 2y = 60 .... (2)

Solving the above system substitute y = 25- x in (1)

we get: 3x + 2y = 60 ⇒ 3x + 2(25 -x) = 60

or, x = 10

⇒ y = 25 - x = 25 - 10 = 15, or y = 15

So, she should make at least 10 necklaces and 15 bracelets to maximize her profit of P = (18 x + 15 y)

8 0

2 years ago

Read 2 more answers

During a sale, 20-cent candy bars were sold at 3 for 50 cents. How much is saved on 9 bars?

Mazyrski [523]

Answer:

Step-by-step explanation:

$0.30

Step-by-step explanation:

1 bar of candy = $0.20

3 bars of candy = $0.50

To solve, multiply for both:

If you pay for each candy bar individually, they each cost $0.20. Multiply 9 with 0.20:

9 x 0.20 = $1.80

If you pay for the candy bars by 3's, they cost $0.50 each pack. Divide 9 with 3, then multiply by 0.50:

9/3 = 3

3 x 0.50 = $1.50

Subtract the total cost of the individual from the pack:

$1.80 - $1.50 = $0.30

. $0.30 is your answer.

8 0

2 years ago

The length of a rectangle is 24 units. can the perimeter x of the rectangle be 60 units when its width y is 11 units? (1 point)

Sergio [31]

Okay, well we start out with the equation P=66, where P is perimeter. You should create equations using variables to explain each piece of information you are given. Follow the equations below and see if you can understand how to do another one like this. In this problem, l is length and w is width.

P = 66 The perimeter is equal to 66

l = 3 + w The length of one side is 3 more than the width

2l + 2w = 66 A rectangle's perimeter is calculated by adding the lengths and widths

2(3 + w) + 2w = 66 Use what you know about length from step 2 to replace the variable in step 3

6 + 2w + 2w = 66 Multiply

6 + 4w = 66 Add like terms

4w = 60 Subtract

w = 15 Divide

l = 3 + w Remember step 2?

l = 3 + 15 Replace the variable using your value for w

l = 18 Add

And you're done! Always check your work. It helps to create a picture of a rectangle while you're doing these problems as well. As you get used to these problems more and more, you can show more or less work than I've shown, but try to stay true to what the teacher asks of you. Good luck!

8 0

2 years ago

Read 2 more answers

The article "Expectation Analysis of the Probability of Failure for Water Supply Pipes"† proposed using the Poisson distribution

oksian1 [2.3K]

Answer:

a. P(X ≤ 5) = 0.999

b. P(X > λ+λ) = P(X > 2) = 0.080

Step-by-step explanation:

We model this randome variable with a Poisson distribution, with parameter λ=1.

We have to calculate, using this distribution, P(X ≤ 5).

The probability of k pipeline failures can be calculated with the following equation:

$P(k)=\lambda^{k} \cdot e^{-\lambda}/k!=1^{k} \cdot e^{-1}/k!=e^{-1}/k!$

Then, we can calculate P(X ≤ 5) as:

$P(X\leq5)=P(0)+P(1)+P(2)+P(4)+P(5)\\\\\\P(0)=1^{0} \cdot e^{-1}/0!=1*0.3679/1=0.368\\\\P(1)=1^{1} \cdot e^{-1}/1!=1*0.3679/1=0.368\\\\P(2)=1^{2} \cdot e^{-1}/2!=1*0.3679/2=0.184\\\\P(3)=1^{3} \cdot e^{-1}/3!=1*0.3679/6=0.061\\\\P(4)=1^{4} \cdot e^{-1}/4!=1*0.3679/24=0.015\\\\P(5)=1^{5} \cdot e^{-1}/5!=1*0.3679/120=0.003\\\\\\P(X\leq5)=0.368+0.368+0.184+0.061+0.015+0.003=0.999$

The standard deviation of the Poisson deistribution is equal to its parameter λ=1, so the probability that X exceeds its mean value by more than one standard deviation (X>1+1=2) can be calculated as:

$P(X>2)=1-(P(0)+P(1)+P(2))\\\\\\P(0)=1^{0} \cdot e^{-1}/0!=1*0.3679/1=0.368\\\\P(1)=1^{1} \cdot e^{-1}/1!=1*0.3679/1=0.368\\\\P(2)=1^{2} \cdot e^{-1}/2!=1*0.3679/2=0.184\\\\\\P(X>2)=1-(0.368+0.368+0.184)=1-0.920=0.080$

4 0

2 years ago