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2 years ago

Assume that triangle GHI is congruent to LMN. Which of the following congruence statement are correct? check all that apply

Mathematics

2 answers:

Vsevolod [243]2 years ago

6 0

Answer.

GH = LM

<N = <I

<M = <H

IH = NM

Just got it wrong on APEX

Airida [17]2 years ago

5 0

If two triangles are congruent, then they have equal corresponding angles and also the sides.
Therefore, if GHI is congruent to LMN, then GH =LM, HI=MN and GI=LN, and also angle G=angle L, Angle H=angle M, while angle I = angle N, therefore the correct answers is a) ∠M= ∠H, c) ∠L=∠G. and e)IH=NM.

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An appliance manufacturer recommends keeping the freezer set at -18 degrees C. Explain what the absolute value tells us about -1

LenaWriter [7]

Answer: I do not know honestly

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2 years ago

A composite figure is comprised of a square, trapezoid, and a rectangle. The square has side lengths of 10 centimeters. The trap

Evgesh-ka [11]

The area of the composite figure is 264 square centimeters, if a composite figure comprised of a square, trapezoid and a rectangle.

Step-by-step explanation:

The given is,

Dimensions of square has length of 10 cm

Trapezoid has base lengths of 8 cm and 14 cm

The length of the trapezoid is 4 cm

Rectangle has side length of 20 cm and 6 cm

Step:1

Area of composite figure = Area of square + Area of Trapezoid

+ Area of rectangle.......................(1)

Step:2

Formula for area of square,

$A_{square} = a^{2}$

where, a - side of length = 10 cm

$=10^{2}$

$=100$

Area of square, $A_{square}$ = 100 Square centimeter

Step:3

Formula for area of Trapezoid,

$A_{Trapezoid}$ = $\frac{a+b}{2} h$ .......................................(2)

Where, a - 8 cm

b - 14 cm

h - 4 cm

From equation (2)

= $\frac{8+14}{2} 4$

= $(11)(4)$

= 44

Area of Trapezoid, $A_{Trapezoid}$ = 44 square centimeters

Step:4

Formula for area of rectangle,

$A_{Rectangle} =lb$ ......................................(3)

Where, l = 20 cm

b = 6 cm

Equation (3) becomes,

$= (20)(6)$

= 120

Area of rectangle, $A_{Rectangle}$ = 120 square centimeters

Step:5

From Equation (1),

$A_{Composite}$ = 100 + 44 + 120

= 264 square centimeters

Result:

The area of the composite figure is 264 square centimeters, if a composite figure comprised of a square, trapezoid and a rectangle.

4 0

2 years ago

Read 2 more answers

19% of a certain population of students at Hardy-Weinberg equilibrium is affected by an autosomal dominant condition called ‘laz

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Answer:

81%

Step-by-step explanation:

Let 'L' be the dominant and 'l' e the recessive allele for ‘lazybuttness’.

Since ‘lazybuttness’ is an autosomal dominant condition, the 19% of students affected by the condition correspond to the homozygous dominant (LL) and heterozygous (Ll) genotypes. Therefore, the rest of the population has the homozygous recessive genotype (ll) and is not affected. The frequency of students not affected is:

F = 100% - 19% = 81%

3 0

1 year ago

Jordan wants to play a basketball game at a carnival. The game costs the player $5 dollar sign, 5 to play, and the player gets t

Alinara [238K]

Answer:

The expected value of Jordan gains is -1 dollar.

Step-by-step explanation:

Consider the following random variables. X := #of shots that Jordan makes. Then, we can can define the random variable Y of the earnings of Jordan in a game as follows

Y = 5 if X=2 (since he gets 10, but invested 5), Y=0 if X=1(since he gets the 5 back) and Y=-5 if X=0(since he doesn't get the money back). Then, in this case, we can define the probability as follows.

P(Y=5) = P(X=2), P(Y=0) = P(X=1), P(Y=-5)= P(X=0).

By definition, the expected value of Y is given by

$E[Y] = 5\cdot P(Y=5)+0\cdot P(Y=0)-5 P(Y=-5)$ . By the previous analysis, we have that

$E[Y] = 5\cdot P(X=2)-5P(X=0)$

We only need to calculate the probabilities for X. In this case, we can consider each shot independt from each other. Then, we can consider X to be distributed as a binomial random variable with n=2 trials and p=0.4 of success (since he has a 40% chance of winning).

Then, by definition

$P(X=k) = \binom{n}{k}p^k(1-p)^{n-k} = \binom{2}{k}0.4^{k}0.6^{2-k}$

where $\binom{n}{k}=\frac{n!}{k!(n-k)!}$

Then,

$P(X=0) = \frac{2!}{0!2!}0.4^{0}0.6^{2} = 0.36$

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Then,

$E[Y] = 5\cdot 0.16-5\cdot 0.36 = -1$

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2 years ago

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evablogger [386]

Let's call the number x. Now, let's make an equation to help us solve this problem.

(((0.43+x)-.58)-4.04) = 30.3
(0.43+x)-4.64 = 30.3
x-4.21 = 30.3
x = 30.3 + 4.21
x = 34.51

The answer is 34.51 and there's the work for you. Have a great day!

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2 years ago

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