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svet-max [94.6K]
1 year ago
12

In one city, 75 percent of residents report that they regularly recycle. In a second city, 90 percent of residents report that t

hey regularly recycle. Simple random samples of 75 residents are selected from each city. Which of the following statements is correct about the approximate normality of the sampling distribution of the difference in sample proportions of residents who report that they regularly recycle?
a. The sampling distribution is approximately normal because both sample sizes are large enough.
b. The sampling distribution is not approximately normal because although the sample size for the first city is large enough, the sample size for the second city is not large enough.
c. The sampling distribution is not approximately normal because although the sample size for the second city is large enough, the sample size for the first city is not large enough.
d. The sampling distribution is not approximately normal because neither sample size is large enough.
e. There is not enough information provided to determine whether the sampling distribution is approximately normal.
Mathematics
1 answer:
Paraphin [41]1 year ago
6 0

can you show me a picture then maybe i can help you

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City planners are creating a 3-dimensional model of a city park to find the best placement for a new tennis court. The city park
inn [45]
First, divide the original measurements with the scaled ones. You'll get the same answer meaning that is the scale used by the model.
1500 ft. ÷7.5 ft = 200
600 ft. ÷ 3 ft. = 200
 
To simply check, if you divide 1500 with 200, the answer is 7.5 and 600 divided by 200 is 3.
To find the  scaled dimension of the tennis court with actual dimension of 120 ft by 60 ft, divide both values with the scale used in the model which is 200.

120 ft. ÷ 200 = 0.6 ft
60 ft. ÷ 200 =  0.3 ft

The dimension of the tennis court in the scaled model is 0.6 ft long and 0.3 ft. wide.

8 0
1 year ago
Cynthia rounds a number, x,to one decimal place. the result is 6.3.
gladu [14]

The answer is: 6.25\leq6.3

The explanation is shown below:

1. Cynthia rounds the number, which is identified as x, to one decimal place and the result is 6.3.

2. Based on this, we know that x could have been between 6.25 and 6.35. Therefore, the error interval for x is given by:

 6.25\leq6.3

Where \leq indicates that the value 6.25 is included and indicates that the value 6.35 is not included (Because if x had been exactly 6.35, Cynthia would round up to 6.4).

7 0
1 year ago
The spinner shown has eight equal-sized sections. The pointer lands on an even number 135 times out of 250 spins. Which of the f
forsale [732]

Answer:

A and D

Step-by-step explanation:

Here, we shall be evaluating the validity of the statements;

A. Yes, A is true

There are four even numbers 2,4,6 and 8 and 4 odd number 1,3,5,7; The landing should be equal at 125 each

B. This is wrong

It is supposed to land half of the number of time s which is half of 250 and that is 125

C.This is wrong

The numbers greater than 4 are 5,6,7,8

Now, the probability should be 4/8 = 1/2 and that is 50%

D. This is correct

Number of times we have a landing on odd numbers is 250-135 = 115

The experimental probability of landing on an odd number is thus 115/250 = 0.46 which is 46%

8 0
2 years ago
robert plant 7 trees behind westwood school. he planted 6 times as many trees in front of the school. how many trees did he plan
Sati [7]
49 in total or 42 trees in the front

4 0
1 year ago
Read 2 more answers
On her first day in a hospital, Kiri receives u1 milligrams (mg) of a therapeutic drug. The amount of the drug Kiri receives inc
Valentin [98]

Answer:

a. 21 = u1 + 6·d

b. 29 = u1 + 10·d

c. d = 2, u1 = 9

Step-by-step explanation:

a. The given parameters are;

The amount of therapeutic drug Kiri receives on her first at the hospital = u1 milligrams

The amount of drug increase received by Kiri each day = d

The amount of drug Kiri received on the seventh day = 21 mg

The amount of drug she received on the eleventh day = 29 mg

Therefore, we have an arithmetic progression with the formula for the nth term given as follows;

aₙ = a₁ + (n - 1)·d

Where;

a₁ = u1

n = The number of terms

Therefore, for the 7th day, the amount of drugs she receives, which is 21 milligrams, is given as follows;

a₇ = u1 + (7 - 1)·d = u1 + 6·d = 21

The equation for the amount of drugs she receives in terms of u1 and d on the seventh day is given as follows;

21 = u1 + 6·d

b. For the eleventh day, the amount of drugs she receives, which is 29 milligrams, is given as follows;

a₁₁ = u1 + (11 - 1)·d = u1 + 10·d = 29

Therefore, the equation for the amount of drugs she receives in terms of u1 and d on the  eleventh day is given as follows;

29 = u1 + 10·d

c. Therefore, we have two equations which are given as follows;

21 = u1 + 6·d................(1)

29 = u1 + 10·d..............(2)

Subtracting equation (1) from equation (2) gives;

29 - 21 = (u1 + 10·d) - (u1 + 6·d)

8 = 4·d

d = 8/4 = 2

d = 2

From equation (1), we have;

21 = u1 + 6·d = u1 + 6×2 = u1 + 12

21 = u1 + 12

21 - 12 = u1

∴ u1 = 9

d = 2, u1 = 9.

4 0
1 year ago
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