Area of a square equals side squared
(A = s²)
30 = s²
√30 = s
You can use a calculator to find out that √30 ≈ 5.48
or you can use estimation (√25 < √30 < √36) which means that √30 is between 5 and 6.
Answer: The drive was 24.32% full when the transfer began.
Step-by-step explanation:
Given: The rate of transferring file = 4.44 megabytes per second.
After 32 seconds, the amount of data on the drive = 384 megabytes
The amount of transferred data =
megabytes
Therefore, the amount of data in the drive at the beginning is given by :-

The drive had a maximum capacity of 1000 megabytes.

Hence, the drive was 24.32% full when the transfer began.
So the given series is "16, 06, 68, 88, __"
Count all the cyclical opening in each of these numbers. For example in 16, there is a one cyclical loop present in it(the one in 6), similarly in 06 it is two(one in zero and one in 6), going ahead, in 68 it is 3(one in 6 and two in 8).
From here on things become simple: hence, the cyclical figures in these equations written down becomes 1,2,3,4,_,3.
Let's now try solving the above sequence, going by the logical reasoning the only number that can fill in the gap should be 4.