D/2=r
vcone=(1/3)hpir^2
given
d=30
h=9.1
d/2=30/2=15=r
v=(1/3)9.1pi15^2
v=(9.1/3)pi225
v=682.5pi
use 3.141592 to aprox pi
v=2144.13654
the closese is the first one
answer would be 2120 m³
Answer:
![4x^5\sqrt[3]{3x}](https://tex.z-dn.net/?f=%204x%5E5%5Csqrt%5B3%5D%7B3x%7D%20)
Step-by-step explanation:
I'm not sure I understand the problem, but I think it's this:
![\sqrt[3]{16x^7} \times \sqrt[3]{12x^9} =](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B16x%5E7%7D%20%5Ctimes%20%5Csqrt%5B3%5D%7B12x%5E9%7D%20%3D%20)
![= \sqrt[3]{16 \times 12 \times x^{16}}](https://tex.z-dn.net/?f=%3D%20%5Csqrt%5B3%5D%7B16%20%5Ctimes%2012%20%5Ctimes%20x%5E%7B16%7D%7D)
![= \sqrt[3]{192 \times x^{15} \times x}](https://tex.z-dn.net/?f=%3D%20%5Csqrt%5B3%5D%7B192%20%5Ctimes%20x%5E%7B15%7D%20%5Ctimes%20x%7D)
![= \sqrt[3]{64 \times 3 \times (x^5)^3 \times x}](https://tex.z-dn.net/?f=%20%3D%20%5Csqrt%5B3%5D%7B64%20%5Ctimes%203%20%5Ctimes%20%28x%5E5%29%5E3%20%5Ctimes%20x%7D%20)
![= \sqrt[3]{4^3 \times 3 \times (x^5)^3 \times x}](https://tex.z-dn.net/?f=%20%3D%20%5Csqrt%5B3%5D%7B4%5E3%20%5Ctimes%203%20%5Ctimes%20%28x%5E5%29%5E3%20%5Ctimes%20x%7D%20)
![= 4x^5\sqrt[3]{3x}](https://tex.z-dn.net/?f=%20%3D%204x%5E5%5Csqrt%5B3%5D%7B3x%7D%20)
1. It is the subset of a group - Group sample.
2. It equally favors all members of a group sample
- Random sample.
3. It collects data on members of a group - Survey.
4. It does not equally favor all members of a group - Biased sample.
5. It includes all members of a group
- Population.
6. It analyzes data collected from a group - Mean.
I have matched all concepts in accordance with statistical use, hope it helps.
Answer: The coordinates of point C after the dilation are (-2, 5)
Step-by-step explanation:
I guess that you want to find where the point C ends after the dilation.
Ok, if we have a point (x, y) and we do a dilation with a scale A around the point (a,b), then the dilated point will be:
(a + A*(x - a), b + A*(y - b))
In this case we have:
(a,b) = (2,1) and A = 3.
And the coordinates of point C, before being dilated, are: (1, 2)
Then the new location of the point C will be:
C' = (1 + 3*(1 - 2), 2 + 3*(2 - 1)) = (1 -3, 2 + 3) = (-2, 5)
Answer:
11 km/hr.
Step-by-step explanation:
Given information:
Simulated speed = 20/km/h
Time = 15 mins = 1/4 hr = 0.25 hr
Distance Covered as per simulated speed = 
Position of Julian according to the app = 
.
Actual distance covered by the bike is
Formula for speed:
Therefore, the average speed of Julian is 11 km/hr.
