Let d^2A/dt^2=6ti-24t^2j+4sintk. Find A given that A=2i+j and dA/dt=-i-3k at t=0 fuu process please to solve??

The bottom of a large theater screen is 3ft above your eye level and the top of the acreen is 10ft above your eye level. Assume

Anna71 [15]

As usual, draw a diagram. You can easily see that if you are x away from the wall,

the angle of elevation of the bottom of the screen (A) is 

cotA = x/3 
A = arccot(x/3) 

angle B to the top is 

cotB = x/10 
B = arccot(x/10) 

So, since θ = B-A 
dθ/dt = dB/dt - dA/dt 
= -3/(x^2+9) + 10/(x^2+100) 
= 7(x^2-30)/((x^2+9)(x^2+100)) 

so, at x=30 
dθ/dt = 203/30300

5 0

1 year ago

You take the four Aces, four $2$'s, and four $3$'s from a standard deck of 52 cards, forming a set of $12$ cards. You then deal

kap26 [50]

Answer:

Probability each player gets an ace, a $2 and a $3 = 0.0374

Step-by-step explanation:

The total number of ways to divide the card in triples among four players = 369600 ways

The total number of ways to share the cards such that no card is repeated in each triple = 13824 ways

Probability each player gets an ace, a $2 and a $3 = 13824/369600

Probability each player gets an ace a $2 and a $3 = 0.0374

Note: Further explanation is provided in the attachment.

8 0

1 year ago

Which equation is the inverse of y = 2x2 – 8?

Marrrta [24]

The inverse of the the function above is y = $\sqrt{\frac{x+8}{2}}$

In order to find the inverse of any function, you need to switch the x and y values. Once you've done that, you need to solve for the new y value. The resulting equation will be your inverse. The work for this one is below.

y = 2x^2 - 8 ----> Switch the terms

x = 2y^2 - 8 ----> Add 8 to both sides.

x + 8 = 2y^2 ----> Divide both sides by 2.

$\frac{x+8}{2}$ = y^2 ----> Now take the square root of both sides.

$\sqrt{\frac{x+8}{2}}$ = y

What's left is your inverse. You can change the order so that it is in a more acceptable form.

y = $\sqrt{\frac{x+8}{2}}$

6 0

2 years ago

Need asap please!!!!!

nevsk [136]

I think its c im pretty sure that it is

8 0

1 year ago

What is the following simplified product? Assume x greater-than-or-equal-to 0 (StartRoot 10 x Superscript 4 Baseline EndRoot min

9966 [12]

Answer:

$\bold{10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}}$

Step-by-step explanation:

To find:

Simplified product of:

$(\sqrt{10x^4}-x\sqrt{5x^2})(2\sqrt{15x^4}+\sqrt{3x^3})$

Solution:

First of all, let us have a look at some of the formula:

1. $(a+b) (c+d) = ac+bc+ad+bd$

2. $a^b\times a^c =a^{b+c }$

3. $\sqrt{a^{2b}} = \sqrt{a^b.a^b}=a^b$

4. $\sqrt a \times \sqrt b = \sqrt{a\times b}$

Now, let us apply the above formula to solve the given expression.

$(\sqrt{10x^4}-x\sqrt{5x^2})(2\sqrt{15x^4}+\sqrt{3x^3})\\\\\Rightarrow(\sqrt{10x^4})(2\sqrt{15x^4})+(\sqrt{10x^4})(\sqrt{3x^3})-(x\sqrt{5x^2})(2\sqrt{15x^4})-(x\sqrt{5x^2})(\sqrt{3x^3})\\\\\Rightarrow2\sqrt{150x^8}+\sqrt{30x^7}-2x\sqrt{75x^6}-x\sqrt{15x^5}\\\\\Rightarrow\bold{10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}}$

The answer is:

$\bold{10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}}$

8 0

1 year ago