Let d^2A/dt^2=6ti-24t^2j+4sintk. Find A given that A=2i+j and dA/dt=-i-3k at t=0 fuu process please to solve??

Nevin made tables of values to approximate the solution to a system of equations. First he found that the x-value of the solutio

prisoha [69]

Answer:

The correct option is B.

Step-by-step explanation:

The given equation are

$y=4x-3$

$y=-5x+9$

On solving both the equation, we get

$4x-3=-5x+9$

$4x+5x=9+3$

$9x=12$

$9x=\frac{12}{9}=\frac{4}{3}$

Put this value in the given equation.

$y=4(\frac{4}{3})-3$

$y=\frac{16}{3}-3$

$y=\frac{16-9}{3}$

$y=\frac{7}{3}$

The solution of the given system of equation is

$(\frac{4}{3},\frac{7}{3})=(1.333,2.333)\approx (1.3,2.3)$

The best approximation of the exact solution is (1.3,2.3). Therefore the correct option is B.

7 0

2 years ago

Read 2 more answers

The label on the car's antifreeze container claims to protect the car between −40°C and 140°C. To covert Celsius temperature to

sergejj [24]

Answer:

-40 < t < 284

Step-by-step explanation:

The antifreeze protects the car between −40°C and 140°C.

Using t for temperature, the compound inequality of the Celsius temperature range is:

-40 < t < 140

The conversion formula is given to find degrees C in given degrees F. We can solve the formula for F, so we get degrees F in terms of degrees C.

C = (5/9)(F - 32) <------ <em>conversion formula from deg F to deg C</em>

Solve for F:

(9/5)C = F - 32

(9/5)C + 32 = F

F = (9/5)C + 32 <------ <em>conversion formula from deg C to deg F</em>

Now we convert -40 deg C to deg F using the formula we just derived.

F = (9/5)C + 32

F = (9/5)(-40) + 32

F = -72 + 32

F = -40

-40 deg C = -40 deg F

(This is not a mistake or a typo. -40 deg C really is the same as -40 deg F.)

Now we convert 140 deg C to deg F using the formula we just derived.

F = (9/5)C + 32

F = (9/5)(140) + 32

F = 252 + 32

F = 284

140 deg C = 284 deg F

Now we rewrite the compound inequality with Fahrenheit temperatures.

-40 < t < 284

4 0

2 years ago

Suppose again that we are counting the ways to distribute exams to TAs and it matters which students' exams go to which TAs. The

abruzzese [7]

The question is incorrect.

The correct question is:

Three TAs are grading a final exam.

There are a total of 60 exams to grade.

(c) Suppose again that we are counting the ways to distribute exams to TAs and it matters which students' exams go to which TAs. The TAs grade at different rates, so the first TA will grade 25 exams, the second TA will grade 20 exams and the third TA will grade 15 exams. How many ways are there to distribute the exams?

Answer: 60!/(25!20!15!)

Step-by-step explanation:

The number of ways of arranging n unlike objects in a line is n! that is ‘n factorial’

n! = n × (n – 1) × (n – 2) ×…× 3 × 2 × 1

The number of ways of arranging n objects where p of one type are alike, q of a second type are alike, r of a third type are alike is given as:

n!/p! q! r!

Therefore,

The answer is 60!/25!20!15!

6 0

2 years ago

A law firm charges a client according to the function f(x)=4(x+2) , where x represents the number of hours spent on the client’s

Zigmanuir [339]

Answer:

The graph in the attached figure

Step-by-step explanation:

Let

x ---> the number of hours spent on the client’s case each week

f(x) ----> the total charge that week in hundreds of dollars

we have

$f(x)=4(x+2)$

distribute

$f(x)=4x+8$

This is the equation of the line in slope intercept form

where

The slope or unit rate is

$m=4$

The y-intercept or initial value is

$b=8$

To graph the line we need minimum two points

Find the x-intercept

For f(x)=0

$0=4x+8\\4x=-8\\x=-2$

The x-intercept is the point (-2,0)

so

we have

the points (-2,0) and (0,8)

To graph the line, plot the intercepts, connect them and join the points

The graph in the attached figure

Remember that the value of x and the value of f(x) cannot be a negative number

3 0

2 years ago

Using V = lwh, what is an expression for the volume of the following prism? The dimensions of a prism are shown. The height is S

Lubov Fominskaja [6]

<h2>Explanation:</h2><h2></h2>

We know that the volume of a prism is defined by:

$V=lwh \\ \\ \\ Where: \\ \\ l:length \\ \\ w:width \\ \\ h:height \\ \\ \\ l=\frac{d-2}{3d-9} \\ \\ w=\frac{4}{d-4} \\ \\ h=\frac{2d-6}{2d-4}$

Substituting values:

$V=\left(\frac{d-2}{3d-9}\right)\left(\frac{4}{d-4}\right)\left(\frac{2d-6}{2d-4}\right) \\ \\ \\ Simplifying: \\ \\ V=\frac{d-2}{3d-9}\cdot \frac{4}{d-4}\cdot \frac{d-3}{d-2} \\ \\ V=\frac{\left(d-2\right)\cdot \:4\left(d-3\right)}{\left(3d-9\right)\left(d-4\right)\left(d-2\right)} \\ \\ V=\frac{4\left(d-3\right)}{\left(3d-9\right)\left(d-4\right)} \\ \\ V=\frac{4\left(d-3\right)}{3\left(d-3\right)\left(d-4\right)}$

$Finally: \\ \\ \boxed{V=\frac{4}{3\left(d-4\right)}}$

4 0

2 years ago

Read 3 more answers