Answer:
Step-by-step explanation:
50 - 31 = 19
38%
Answer:
Total amount pay after 3 week = $147.5
Step-by-step explanation:
Given:
Amount of loan taken = $125
Amount interest per $100 = $6 per week
Find:
Total amount pay after 3 week
Computation:
Amount of interest per week = 125[6/100]
Amount of interest per week = $7.5 per week
Amount of interest in three week = 3 x Amount of interest per week
Amount of interest in three week = 3 x 7.5
Amount of interest in three week = $22.5
Total amount pay after 3 week = Amount of loan taken + Amount of interest in three week
Total amount pay after 3 week = 125 + 22.5
Total amount pay after 3 week = $147.5
Step-by-step explanation:
Since f(0) = f(5) = f(8) = 0, we have f(x) = Ax(x - 5)(x - 8), where A is a real constant.
We know that f(10) = 17.
=> A(10)(10 - 5)(10 - 8) = 17
=> A(10)(5)(2) = 17
=> 100A = 17, A = 0.17.
Hence the answer is f(x) = 0.17x(x - 5)(x - 8).
The answer is 1 gallon.
Miles per gallon(mpg) is computed by dividing the distance traveled by the how many gallons used. So you can derive a formula for how many gallons you would use given the mpg. You will end up with:

The problem asks for how many gallons of gas she will safe in a five-day work work week. So first you need to compute how many miles that would be.
54 miles/day x 5days =
270 milesSo in a five day work week, she will travel 270 miles.
Now to see how much gas she will save, compute how many gallons she will use up for each car, given the mpg of each and find the difference.
First model:30 mpg

This means that with the first model, she will have used up
9 gallons in a 5-day work week.
Second model: 27 mpg


This means that with the second model, she will have used up 10g in a 5-day work week.
Now for the last bit. How much will she save? You can get that by getting the difference of how many gallons each car would have used up.
10gallons - 9gallons = 1gSo she would have saved
1 gallon of gas if she buys the first car instead of the second.
Digit numbers.
Let the numbers 00 to 89 represent that the train is on time.
Let the numbers between 90 and 99 represent that the train is late.
Randomly select 6 numbers, with repetition allowed.
Count the number of times the train is late.
Repeat this simulation multiple times.
You will most likely obtain a result of between 0 and 2 times that the train is late.