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2 years ago

If FC IS RS 4430 and the BEP in unitsis 89, then contribution margin is ?

Mathematics

1 answer:

Umnica [9.8K]2 years ago

5 0

Answer: RS 49.8

Step-by-step explanation:

Given the following :

Fixed cost = RS 4430

Break even point = 89 units

Recall:

Break even point in units = Fixed cost ÷ contribution margin

Therefore,

Contribution margin equals;

(Fixed cost ÷ break even point in units)

= 4430 / 89

= 49.775280

= RS 49.8

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Explain how your work your knowledge of place value helps you divide a number in thousands by whole numbers to 10 give a example

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2 years ago

A county is in the shape of a rectangle that is 60 miles by 70 miles and has a population of 50,000. What is the average number

lakkis [162]

Answer:

The correct answer is:

Step-by-step explanation:

Length of county = 70 miles

breadth of county = 60 miles

area of county (rectangle) = Length × Breadth = 60 × 70 = 4,200 sqaure miles

population of county = 50,000

Therefore, to find the average number of people living on each square mile of the county, we will assume that the whole population is equally distributed in the county, hence the population per square mile is calculated thus:

Total area = 4,200 square miles

total population = 50,000

This means that:

4,200 square miles contains 50,000 people

4,200 sq. miles = 50,000 people

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2 years ago

One of your peers claims that boys do better in math classes than girls. Together you run two independent simple random samples

JulijaS [17]

Answer:

Step-by-step explanation:

Hello!

To test if boys are better in math classes than girls two random samples were taken:

Sample 1

X₁: score of a boy in calculus

n₁= 15

X[bar]₁= 82.3%

S₁= 5.6%

Sample 2

X₂: Score in the calculus of a girl

n₂= 12

X[bar]₂= 81.2%

S₂= 6.7%

To estimate per CI the difference between the mean percentage that boys obtained in calculus and the mean percentage that girls obtained in calculus, you need that both variables of interest come from normal populations.

To be able to use a pooled variance t-test you have to also assume that the population variances, although unknown, are equal.

Then you can calculate the interval as:

[(X[bar]_1-X[bar_2) ± $t_{n_1+n_2-2;1-\alpha /2}$ * $Sa*\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }$ ]

$Sa= \sqrt{\frac{(n_1-1)S^2_1+(n_2-1)S^2_2}{n_1+n_2-2} } = \sqrt{\frac{14*(5.6^2)+11*(6.7^2)}{15+12-2} }= 6.108= 6.11$

$t_{n_1+n_2-2;1-\alpha /2}= t_{15+12-2;1-0.05}= t_{25;0.95}= 1.708$

[(82.3-81.2) ± 1.708* (6.11* $\sqrt{\frac{1}{15}+\frac{1}{12} }$ ]

[-2.94; 5.14]

Using a 90% confidence level you'd expect the interval [-2.94; 5.14] to contain the true value of the difference between the average percentage obtained in calculus by boys and the average percentage obtained in calculus by girls.

I hope this helps!

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