Answer:
![[0,Z_n]](https://tex.z-dn.net/?f=%5B0%2CZ_n%5D)
Step-by-step explanation:
Z = the sales tax percentage for a randomly selected amazon purchase, where n = the total number of possible sales tax percentages for online purchases
Since Amazon is an online purchase, The set of possible values for the variable is a positive real number. It is a positive real number that must be within 
. It cannot exceed the tax percentage for online purchases that can be found in Amazon. is a set of online purchases that can be found on Amazon, therefore the set of possible values for the variable is
Answer:
16% probability that the facility needs to recalibrate their machines.
Step-by-step explanation:
We have to use the Empirical Rule to solve this problem.
Empirical Rule:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
What is the probability that the facility needs to recalibrate their machines?
They will have to recalibrate if the number of defects is more than one standard deviation above the mean.
We know that by the Empirical Rule, 68% of the measures are within 1 standard deviation of the mean. The other 100-68 = 32% is more than 1 standard deviation from the mean. Since the normal distribution is symmetric, of those 32%, 16% are more than one standard deviation below the mean, and 16% are more than one standard deviation above the mean.
So there is a 16% probability that the facility needs to recalibrate their machines.
Answer:
£265
Step-by-step explanation:
Total fraction of money spent= 
= 
Actual money spent = * £636
= £371
Money he has left = £(636 - 371)
= £265
Answer:
The answer is "Screen B is wider , because 5.3 is greater than 5 and one-third".
Step-by-step explanation:
The mobile display unit must be made similar. Phone A uses a decimal device, and telephone B uses a fraction in this case.
It's easier for you to use. Attempt using the decimal. The width of the phone B fraction could then be translated to decimal width. The computing is:
= 5 cm + 
cm
= 5 cm + 0.333cm
= 5.333 cm
It is evident from here that the wider screen of Phone B is than that of Phone A.
The area of a rectangle is equal L x W
4 cm longer than it is wide L = 4 + <span>W
</span>
L x W = 117 we replace L here
(4 + <span>W ) x W = 117
</span>
4W + W ^2 = 117
<span>4W + W ^2 -117 = 0
</span>W ^2 +4 W -117 = 0
W² + 4W - 117 = 0
<span>
THEN u want to use the </span>use the quadratic formula
OR Factoring gives us
(W + 13)(W - 9) = 0
W = -13 or 9
But it can't be negative, so
W = 9 and L= 9+4 = 13
