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krek1111 [17]
1 year ago
15

Luke receives an electric bill of \$84.21$84.21dollar sign, 84, point, 21 for the month of April. The electric company charges \

$0.14$0.14dollar sign, 0, point, 14 per kilowatt-hour (\text{kWh})(kWh)left parenthesis, start text, k, W, h, end text, right parenthesis of electricity. Given that April has 303030 days, about how many kilowatt-hours did Luke use per day during the month of April?
Mathematics
1 answer:
Elena L [17]1 year ago
6 0

Answer:

20.05 kilowatt-hour

Step-by-step explanation:

Total electric bill = $84.21

Charges per kilowatt-hour = $0.14

Days in April = 30 days

Number of hours = x

Total electric bill = Charges per kilowatt-hour × Days in April × Number of hours

84.21 = 0.14 * 30 * x

84.21 = 4.2 * x

84.21 = 4.2x

Divide both sides by 4.2

x = 84.21 / 4.2

= 20.05

x = 20.05 kilowatt-hour

Therefore, Luke use 20.05 kilowatt-hour per day during the month of April

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*Given
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*Solution 

1. The given equation is 3(x+y) = y and we are tasked to find the ratio between x and y. Distributing 3 to the terms in the parenthesis, 

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