Actually there is enough information to solve this
problem. First, let us find the total per row and per column.
(see attached pic)
P(Grade 10 | opposed) with P(opposed | Grade 10)
P(Grade 10 | opposed) = Number in Grade 10 who are opposed
/ Total number of Opposed (column)
P(Grade 10 | opposed) = 13 / 41 = 0.3171
P(opposed | Grade 10) = Number in Grade 10 who are opposed
/ Total number in Grade 10 (row)
P(opposed | Grade 10) = 13 / 32 = 0.4063
Therefore:
P(Grade 10 | opposed) IS NOT EQUAL P(opposed | Grade 10),
hence they are dependent events.
Answer:
P(Grade 10 | opposed) < P(opposed | Grade 10)
Answer:
Choices are missing here.
However, we can find the plot that represents the data.
To draw a scatterplot, we just need to draw points, where the indepedent variable is going to be 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, that is the position of each player.
So, all points we need to draw the plot are:
(1, 28)
(2, 13)
(3, 4)
(4, 8)
(5, 15)
(6, 10)
(7, 22)
(8, 7)
(9, 11)
(10, 15)
The image attached shows the plot that represents this data set.
Mean = Sum of all the observations/ Number of observations = (87+46+90+78+89)/5 = 78
Variance = SD^2 ------ SD = Standard deviation
It means that with Variance, square root is never taken.
Therefore,
Variance = Summation of square of differences between observation and the mean divided by the number of observations.
That is,
Variance = {(87-78)^2 + (46-78)^2 + (90-78)^2 + (78-78)^2 + (89-78)^2}/5 = 274
Answer:
<x = 31°
Step-by-step explanation:
m<BCA = m<GCJ (vertical angles)
m<BCA = 59° (substitution)
Since line KL is perpendicular to line FG, the angle formed at point B is 90°.
Therefore, m<ABC = 90°
m<BAC + m<ABC + m<BCA = 180° (sum of triangle)
m<BAC + 90° + 59° = 180° (Substitution)
m<BAC + 149° = 180°
m<BAC = 180° - 149°
m<BAC = 31°
<x = <BAC (vertical angles)
m<x = 31° (substitution)
Answer:
The water level rising when the water is 4 inches deep is
.
Step-by-step explanation:
Rate of water pouring out in the cone = R=
Height of the cup = h = 6 inches
Radius of the cup = r = 3 inches

r = h/2
Volume of the cone = 






h = 4 inches



The water level rising when the water is 4 inches deep is
.