Answer:
$95.78
Step-by-step explanation:
f(t) = 300t / (2t² + 8)
t = 0 corresponds to the beginning of August. t = 1 corresponds to the end of August. t = 2 corresponds to the end of September. So on and so forth. So the second semester is from t = 5 to t = 10.
$T₂ = ∫₅¹⁰ 300t / (2t² + 8) dt
$T₂ = ∫₅¹⁰ 150t / (t² + 4) dt
$T₂ = 75 ∫₅¹⁰ 2t / (t² + 4) dt
$T₂ = 75 ln(t² + 4) |₅¹⁰
$T₂ = 75 ln(104) − 75 ln(29)
$T₂ ≈ 95.78
Answer:
a) (0.5256,0.5944)
c) Criticism is invalid
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 560
Proportion of mislabeled = 56%

a) 90% Confidence interval:


Putting the values, we get:

b) Interpretation of confidence interval:
We are 90% confident that the true proportion of all seafood in the country that is mislabeled or misidentified is between 0.5256 and 0.5944 that is 52.56% and 59.44%.
c) Validity of criticism
Conditions for validity:

Verification:

Both the conditions are satisfied. This, the criticism is invalid.
5c+10a=3570
c+a=512
...
a=512-c
so ...
5c + 10(512-c)=3570
Remember
xyz=(x)(y)(z)
if x and y and z are all perfect cubes, xyz is also a perfect cube
remmeber
(x^n)^m=x^(mn)
so if it is perfect cube it can be factored into
(x^n)^3, such taht n is a whole number
basiclaly, see if the expoent is divisble by 3
all of them should be perfect cubes
215x^18y^3z^21
split them up to see which ones need changing
215=5*43, not a perfect cube
could be changed to 6^3, which is 216
x^18=(x^6)^3
y^3=y^3
z^21=(z^7)^3
the 215 needs to be changed
Answer:
-0.5, 2, 4.5, 7, 9.5
Step-by-step explanation:
The given terms are 6 apart, so the common difference is 1/6 of their difference:
d = (12 -(-3))/6 = 15/6 = 5/2 = 2.5
Add 2.5 to each term to get the next one. Then the sequence is ...
-3, <u>-0.5</u>, <u>2.0</u>, <u>4.5</u>, <u>7.0</u>, <u>9.5</u>, 12