Answer:
Step-by-step explanation:
Hello!
You need to construct a 95% CI for the population mean of the length of engineering conferences.
The variable has a normal distribution.
The information given is:
n= 84
x[bar]= 3.94
δ= 1.28
The formula for the Confidence interval is:
x[bar]±
*(δ/n)
Lower bound(Lb): 3.698
Upper bound(Ub): 4.182
Error bound: (Ub - Lb)/2 = (4.182-3.698)/2 = 0.242
I hope it helps!
Answer:
3
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given that X is a normal random variable with parameters µ = 10 and σ 2 = 36,
X is N(10, 6)
Or z = 
is N(0,1)
a) P(X > 5),
=
(b) P(4 < X < 16),
=
(c) P(X < 8),
=
(d) P(X < 20),
=
(e) P(X > 16).
=P(Z>-0.6667)
= 0.2524
Express tan in terms of sin and cos
= sin ax cos bx / sin bx
Now I'm stuck! sorry
For what its worth Ive drawn the graph and the answer is a/b
Answer:
It is more convenient
Step-by-step explanation:
First having in account than the uniform distribution all the points has the same probability, any point has more probability than others, for this reason all the points are equally convenient.
In this, the reason because is more convenient to have four stations is that these are equally distributed and are more stations.