Using the digits 1-9 each only once, create three equivalent ratios..

It is computed that when a basketball player shoots a free throw, the odds in favor of his making it are 2020 to 99. Find the p

dolphi86 [110]

Answer:

Step-by-step explanation:

Given that when a basketball player shoots a free throw, the odds in favor of his making it are 2020 to 99.

Prob that he shoots a free throw = $\frac{99}{2020+99} =0.04672$

a) Probability that when this basketball player shoots a free throw, he misses it=1-0.04672 = 0.95328

b) When no of throws = 100 average of throws he makes is

Since x no of throws he makes has two outcomes and each trial is independent , X is binomial with n =100 and p = 0.04672

Expected value of throws = np = 4.672

6 0

2 years ago

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One of the byproducts of nuclear power generation is Uranium-233. Uranium is decaying at a constant 57% rate per day. If 3,820 p

yanalaym [24]

Given that the decay rate of the uranium is given to be 57%, this means that on the second day only 43% of the Uranium-233 will be left. The equation therefore, that will allow us to answer the question is that,
A(t) = A(0)(1 - r)^n
where A(t) is the amount after n days, A(0) is the original amount, r is the decimal equivalent of the rate and n is the number of days. Substituting the known values,
A(t) = (3,820 pounds)*(1-0.57)^15
A(t) = 0.0121 pounds
This is unfortunately not found in the choices.

3 0

2 years ago

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Suppose that the researchers wanted to estimate the mean reaction time to within 6 msec with 95% confidence. Using the sample st

Lisa [10]

Answer:

a) The 95% confidence interval would be given by (509.592;550.308)

b) n=523 rounded up to the nearest integer

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=530$ represent the sample mean for the sample

$\mu$ population mean

s=70 represent the sample standard deviation

n=48 represent the sample size (variable of interest)

Confidence =95% or 0.995

Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are df=n-1=48-1=47

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,47)".And we see that $z_{\alpha/2}=2.01$

Now we have everything in order to replace into formula (1):

$530-2.01\frac{70}{\sqrt{48}}=509.692$

$530+2.01\frac{70}{\sqrt{48}}=550.308$

So on this case the 95% confidence interval would be given by (509.592;550.308)

Part b

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

Assuming that $\hat \sigma =s$

And on this case we have that ME =6msec, and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 95% of confidence interval is provided, $z_{\alpha/2}=1.96$ , replacing into formula (b) we got:

$n=(\frac{1.96(70)}{6})^2 =522.88 \approx 523$

So the answer for this case would be n=523 rounded up to the nearest integer

3 0

2 years ago

Monica found the volume of the prism below using the expression 4 + (4 times one-half). A prism has a length of 2 centimeters, h

Sphinxa [80]

Answer:

i think its A and D

Step-by-step explanation:

sry if im wrong

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2 years ago

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The ball bearing have volumes of 1.6cm cube and 5.4cm cube . Find the ratio of their surface area.

Korvikt [17]

Answer:

4/9

Step-by-step explanation:

The scale factor for the linear dimensions of the ball bearings will be the cube root of the volume scale factor:

k = ∛(1.6/5.4) = 2/3

Then the scale factor for the areas will be the square of this scale factor:

ratio of surface area = (2/3)² = 4/9

_____

The area is the product of two linear dimensions, so its scale factor is the product of the linear dimension scale factors. That is, the scale factor for area is the square of the linear dimension scale factor.

Similarly, volume is the product of three linear dimensions, so its scale factor is the cube of the linear dimension scale factor.

8 0

2 years ago