let's say the point dividing JK is say point P, so the JK segment gets split into two pieces, JP and PK
![\bf ~~~~~~~~~~~~\textit{internal division of a line segment} \\\\\\ J(-25,10)\qquad K(5,-20)\qquad \qquad \stackrel{\textit{ratio from J to K}}{7:3} \\\\\\ \cfrac{J~~\begin{matrix} P \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{~~\begin{matrix} P \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~K} = \cfrac{7}{3}\implies \cfrac{J}{K} = \cfrac{7}{3}\implies3J=7K\implies 3(-25,10)=7(5,-20)\\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~~~~~~~%5Ctextit%7Binternal%20division%20of%20a%20line%20segment%7D%20%5C%5C%5C%5C%5C%5C%20J%28-25%2C10%29%5Cqquad%20K%285%2C-20%29%5Cqquad%20%5Cqquad%20%5Cstackrel%7B%5Ctextit%7Bratio%20from%20J%20to%20K%7D%7D%7B7%3A3%7D%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7BJ~~%5Cbegin%7Bmatrix%7D%20P%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%7B~~%5Cbegin%7Bmatrix%7D%20P%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~K%7D%20%3D%20%5Ccfrac%7B7%7D%7B3%7D%5Cimplies%20%5Ccfrac%7BJ%7D%7BK%7D%20%3D%20%5Ccfrac%7B7%7D%7B3%7D%5Cimplies3J%3D7K%5Cimplies%203%28-25%2C10%29%3D7%285%2C-20%29%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\bf P=\left(\frac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \frac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)\\\\[-0.35em] ~\dotfill\\\\ P=\left(\cfrac{(3\cdot -25)+(7\cdot 5)}{7+3}\quad ,\quad \stackrel{\textit{y-coordinate}}{\cfrac{(3\cdot 10)+(7\cdot -20)}{7+3}}\right) \\\\\\ P=\left( \qquad ,\quad \cfrac{30-140}{10} \right)\implies P=\left(\qquad ,~~\cfrac{-110}{10} \right)\implies P=(\qquad ,\quad -11)](https://tex.z-dn.net/?f=%5Cbf%20P%3D%5Cleft%28%5Cfrac%7B%5Ctextit%7Bsum%20of%20%22x%22%20values%7D%7D%7B%5Ctextit%7Bsum%20of%20ratios%7D%7D%5Cquad%20%2C%5Cquad%20%5Cfrac%7B%5Ctextit%7Bsum%20of%20%22y%22%20values%7D%7D%7B%5Ctextit%7Bsum%20of%20ratios%7D%7D%5Cright%29%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20P%3D%5Cleft%28%5Ccfrac%7B%283%5Ccdot%20-25%29%2B%287%5Ccdot%205%29%7D%7B7%2B3%7D%5Cquad%20%2C%5Cquad%20%5Cstackrel%7B%5Ctextit%7By-coordinate%7D%7D%7B%5Ccfrac%7B%283%5Ccdot%2010%29%2B%287%5Ccdot%20-20%29%7D%7B7%2B3%7D%7D%5Cright%29%20%5C%5C%5C%5C%5C%5C%20P%3D%5Cleft%28%20%5Cqquad%20%2C%5Cquad%20%5Ccfrac%7B30-140%7D%7B10%7D%20%5Cright%29%5Cimplies%20P%3D%5Cleft%28%5Cqquad%20%2C~~%5Ccfrac%7B-110%7D%7B10%7D%20%5Cright%29%5Cimplies%20P%3D%28%5Cqquad%20%2C%5Cquad%20-11%29)
Check the picture below.
is not very specific above, but sounds like it's asking for an equation for the trapezoid only, mind you, there are square tiles too.
but let's do the trapezoid area then,
![\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad \sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\ -------------------------------\\\\](https://tex.z-dn.net/?f=%5Cbf%20a%5E%7B%5Cfrac%7B%7B%20n%7D%7D%7B%7B%20m%7D%7D%7D%20%5Cimplies%20%20%5Csqrt%5B%7B%20m%7D%5D%7Ba%5E%7B%20n%7D%7D%20%5Cqquad%20%5Cqquad%0A%5Csqrt%5B%7B%20m%7D%5D%7Ba%5E%7B%20n%7D%7D%5Cimplies%20a%5E%7B%5Cfrac%7B%7B%20n%7D%7D%7B%7B%20m%7D%7D%7D%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C)
Answer: 
Step-by-step explanation:
Given the following expresion provided in the exercise:

You can follow these steps in order to evaluate it when
and
:
1. You need to substitute
and
into the given expression:

2. Now you can solve the mutiplication:

3. Since
, you get:

4. You must solve the division. Divide the numerator 16 by the denominator 4. Then:

5. And finally, you must solve the addition. So, you get this result:

Answer:

Step-by-step explanation:
Let
x -----> the number of days
y ----> the number of minutes Yuson has left
we know that
The linear equation in slope intercept form is equal to

where
m is the slope
b is the y-coordinate of the y-intercept (initial value)
In this problem we have
The slope is equal to
----> is negative because is a decreasing function
----> initial value
substitute the values

Answer:
8 helicopters at most
Step-by-step explanation:
I worked on this problem and that was the answer not 99 like the other.