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Vinil7 [7]
1 year ago
8

A new drug on the market is known to cure 30% of patients with cervical cancer. If a group of 18 patients is randomly selected,

what is the probability of observing, at most, one patient who will be cured of cervical cancer?
Mathematics
1 answer:
Dima020 [189]1 year ago
5 0

Answer:

Probability cured of cervical cancer =  18C0 (0.30)⁰(0.70)¹⁸ +  18C1(0.30)(0.70)¹⁷

Step-by-step explanation:

Given:

Patients cured = 30% = 0.30

Number of patients (n) = 18

Probability cured of cervical cancer = P(X≤1)

Probability cured of cervical cancer  = P(X=0) + P(X=1)

Probability cured of cervical cancer =  18C0 (0.30)⁰(0.70)¹⁸ +  18C1(0.30)(0.70)¹⁷

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The endpoints of JK are J(–25, 10) and K(5, –20). What is the y-coordinate of point L, which divides JK into a 7:3 ratio? a. –16
Andrews [41]

let's say the point dividing JK is say point P, so the JK segment gets split into two pieces, JP and PK

\bf ~~~~~~~~~~~~\textit{internal division of a line segment} \\\\\\ J(-25,10)\qquad K(5,-20)\qquad \qquad \stackrel{\textit{ratio from J to K}}{7:3} \\\\\\ \cfrac{J~~\begin{matrix} P \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{~~\begin{matrix} P \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~K} = \cfrac{7}{3}\implies \cfrac{J}{K} = \cfrac{7}{3}\implies3J=7K\implies 3(-25,10)=7(5,-20)\\\\[-0.35em] ~\dotfill

\bf P=\left(\frac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \frac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)\\\\[-0.35em] ~\dotfill\\\\ P=\left(\cfrac{(3\cdot -25)+(7\cdot 5)}{7+3}\quad ,\quad \stackrel{\textit{y-coordinate}}{\cfrac{(3\cdot 10)+(7\cdot -20)}{7+3}}\right) \\\\\\ P=\left( \qquad ,\quad \cfrac{30-140}{10} \right)\implies P=\left(\qquad ,~~\cfrac{-110}{10} \right)\implies P=(\qquad ,\quad -11)

8 0
2 years ago
Read 2 more answers
Paulina is remodeling her bathroom. the tile she has chosen are squares and trapezoids. the side length of each square inthe til
NemiM [27]
Check the picture below.

is not very specific above, but sounds like it's asking for an equation for the trapezoid only, mind you, there are square tiles too.

but let's do the trapezoid area then, 

\bf a^{\frac{{ n}}{{ m}}} \implies  \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
-------------------------------\\\\

\bf A=\cfrac{h(a+b)}{2}\quad 
\begin{cases}
A=At\\
a=x\\
h=x\\
b=2x
\end{cases}\implies At=\cfrac{x(x+2x)}{2}
\\\\\\
At=\cfrac{x(3x)}{2}\implies At=\cfrac{3x^2}{2}\impliedby \textit{now, solving for \underline{x}}
\\\\\\
2At=3x^2\implies \cfrac{2At}{3}=x^2\implies \sqrt{\cfrac{2At}{3}}=x\implies \left( \frac{2At}{3} \right)^{\frac{1}{2}}=x

8 0
2 years ago
Evaluate 10m +\dfrac {n^2}410m+ 4 n 2 ​ 10, m, plus, start fraction, n, squared, divided by, 4, end fraction when m=5m=5m, equal
Readme [11.4K]

Answer: 54

Step-by-step explanation:

Given the following expresion provided in the exercise:

10m+\frac{n^2}{4}

You can follow these steps in order to evaluate it when m=5 and n=4:

1. You need to substitute m=5 and n=4 into the given expression:

10(5)+\frac{(4)^2}{4}

2. Now you can solve the mutiplication:

=50+\frac{(4)^2}{4}

3. Since 4^2=4*4, you get:

=50+\frac{16}{4}

4. You must solve the division. Divide the numerator 16 by the denominator 4. Then:

=50+4

5. And finally, you must solve the addition. So, you get this result:

=54

3 0
2 years ago
Yuson must complete 210 min of community service. She does 30 min each day. Which linear equation represents the number of minut
Misha Larkins [42]

Answer:

y=-30x+210

Step-by-step explanation:

Let

x -----> the number of days

y ----> the number of minutes Yuson has left

we know that

The linear equation in slope intercept form is equal to

y=mx+b

where

m is the slope

b is the y-coordinate of the y-intercept (initial value)

In this problem we have

The slope is equal to

m=-30\frac{min}{day} ----> is negative because is a decreasing function

b=210\ min ----> initial value

substitute the values

y=-30x+210

3 0
2 years ago
Milena wants to power toy cars and helicopters using batteries. Her goal is to power at least 11 toys with a most 60 batteries .
Anni [7]

Answer:

8 helicopters at most

Step-by-step explanation:

I worked on this problem and that was the answer not 99 like the other.

6 0
2 years ago
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