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1 year ago

5

Milena wants to power toy cars and helicopters using batteries. Her goal is to power at least 11 toys with a most 60 batteries .

What is the greatest number of helicopters milena can power while meeting her both constraints

1 answer:

Anni [7]1 year ago

6 0

Answer:

8 helicopters at most

Step-by-step explanation:

I worked on this problem and that was the answer not 99 like the other.

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Find the values of y = r(x) = ∛x for x = –2.197, –1.331, 0, 1.331, 2.197, 3.375, 4.913 Then plot the corresponding points on a g

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The cube root values and a graph of them are shown in the attachment.

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The cube root of a negative number is negative. These all have exact (rational) cube roots.

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2 years ago

Daisy works at an ice-cream parlor. She is paid $10 per hour for the first 8 hours she works in a day. For every extra hour she

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Answer:

80+(15x)

Step-by-step explanation:

10 times 8=80

1.5 times 10=15

so she gets 80 dollars for the first 8 hours then for every extra hour she gets 15 dollars

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2 years ago

Sue had finished three Christmas gifts before the first of December. After that she finished one gift each day. Which equation d

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2 years ago

There is a point $A$ with positive coordinates such that the sum of the coordinates of $A$ is $14$. If the $x$-coordinate of $A$

ch4aika [34]

Answer:

5

Step-by-step explanation:

<u>Given</u>:

A = (a, 14-a)

P = (3a, a^2 +13a -11)

the slope of AP is 7

a > 0

<u>Find</u>:

a

<u>Solution</u>:

The slope of AP is ...

m = (Py -Ay)/(Px -Ax)

7 = (a^2 +13a -11 -(14 -a))/(3a -a)

14a = a^2 +14a -25

25 = a^2

a = √25 = 5 . . . . . the positive solution

The value of 'a' is 5.

_____

<em>Check</em>

The point A is (a, 14-a) = (5, 9).

The point P is (3a, a^2 +13a -11) = (15, 79)

The slope of AP is (79 -9)/(15 -5) = 70/10 = 7.

6 0

1 year ago

Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.Tiles

Ugo [173]

By definition, the average rate of change is given by:

$AVR = \frac{f(x2)-f(x1)}{x2-x1}$

We evaluate each of the functions in the given interval.

We have then:

For f (x) = x ^ 2 + 3x:

Evaluating for x = -2:

$f (-2) = (-2) ^ 2 + 3 (-2)\\f (-2) = 4 - 6\\f (-2) = - 2$

Evaluating for x = 3:

$f (3) = (3) ^ 2 + 3 (3)\\f (3) = 9 + 9\\f (3) = 18$

Then, the AVR is:

$AVR = \frac{18-(-2)}{3-(-2)}$

$AVR = \frac{18+2}{3+2}$

$AVR = \frac{20}{5}$

$AVR = 4$

For f (x) = 3x - 8:

Evaluating for x =4:

$f (4) = 3 (4) - 8\\f (4) = 12 - 8\\f (4) = 4$

Evaluating for x = 5:

$f (5) = 3 (5) - 8\\f (5) = 15 - 8\\f (5) = 7$

Then, the AVR is:

$AVR = \frac{7-4}{5-4}$

$AVR = \frac{3}{1}$

$AVR = 3$

For f (x) = x ^ 2 - 2x:

Evaluating for x = -3:

$f (-3) = (-3) ^ 2 - 2 (-3)\\f (-3) = 9 + 6\\f (-3) = 15$

Evaluating for x = 4:

$f (4) = (4) ^ 2 - 2 (4)\\f (4) = 16 - 8\\f (4) = 8$

Then, the AVR is:

$AVR = \frac{8-15}{4-(-3)}$

$AVR = \frac{-7}{4+3}$

$AVR = \frac{-7}{7}$

$AVR = -1$

For f (x) = x ^ 2 - 5:

Evaluating for x = -1:

$f (-1) = (-1) ^ 2 - 5\\f (-1) = 1 - 5\\f (-1) = - 4$

Evaluating for x = 1:

$f (1) = (1) ^ 2 - 5\\f (1) = 1 - 5\\f (1) = - 4$

Then, the AVR is:

$AVR = \frac{-4-(-4)}{1-(-1)}$

$AVR = \frac{-4+4}{1+1}$

$AVR = \frac{0}{2}$

$AVR = 0$

Answer:

from the greatest to the least value based on the average rate of change in the specified interval:

f(x) = x^2 + 3x interval: [-2, 3]

f(x) = 3x - 8 interval: [4, 5]

f(x) = x^2 - 5 interval: [-1, 1]

f(x) = x^2 - 2x interval: [-3, 4]

4 0

1 year ago