You toss a fair coin 10000 times. what are the odds of obtaining more than 5100 tails, approximately?
1 answer:
This can be solved by using the normal approximation to the binomial distribution.
mean = np = 10.000 * 0.5 = 5,000
The standard deviation is given by:
The probability of obtaining more than 5100 tails is 0.0228 and the probability of obtaining fewer than 5100 tails is 0.9772.
The odds of obtaining more than 5100 tails is therefore:
0.0228:0.9772 = 1:42.86.
mean = np = 10.000 * 0.5 = 5,000
The standard deviation is given by:
The probability of obtaining more than 5100 tails is 0.0228 and the probability of obtaining fewer than 5100 tails is 0.9772.
The odds of obtaining more than 5100 tails is therefore:
0.0228:0.9772 = 1:42.86.
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=> 235 + 123
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=> 235 + 123
Starting from 0 you count 1 up to 235. Then starting from 235 you additionally count another 123.
Then from zero start counting the total number to the line you stopped when adding 123 to 235.
This simply equals to
=> 235 + 123
=> 358.
Pls. see attached image for illustration of number line.</span>Answer here
Answer:
Step-by-step explanation:
We have been given a parallelogram. We are asked to solve for the values of x and y.
We know that opposite sides of parallelogram are equal, so we can set equation as:
Similarly, we will solve for y.
To solve for z, we will subtract y from x as:
Therefore, the value of z is negative 3.