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Nezavi [6.7K]
2 years ago
15

X - 4 = 10 A) x = 3 B) x = 6 C) x = 12 D) x = 14

Mathematics
2 answers:
hjlf2 years ago
7 0

x=14


Add 4 to both sides to isolate x

Tanzania [10]2 years ago
3 0

Answer:

D) x = 14

Step-by-step explanation:

X - 4 = 10

Add 4 to each side

x-4+4 = 10+4

x = 14

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Which shows one way to determine the factors of 12x3 – 2x2 + 18x – 3 by grouping?
Debora [2.8K]

Option A

2x^2(6x-1) + 3(6x-1) is one way to determine the factors of 12x^3-2x^2+18x-3 by grouping

<em><u>Solution:</u></em>

Factoring by grouping means that you will group terms with common factors before factoring

<em><u>Given expression is:</u></em>

12x^3-2x^2+18x-3

Group the first two terms together and then the last two terms together.

(12x^3-2x^2)+(18x-3)

We can see that 2x^2 is common in first two terms

And 3 is common in last two terms

Factor them out

(12x^3-2x^2)+(18x-3) = 2x^2(6x-1) + 3(6x-1)

2x^2(6x-1) + 3(6x-1)

Thus option A is correct

6 0
2 years ago
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Anita is a door-to-door saleswoman for a company selling bedcovers. The company pays her a fixed salary of Rs W every month and
lorasvet [3.4K]

Given:

Anita's fixed salary = Rs. W

Bonus = Rs. Z for every bedcover sold by her.

To find:

Her total earnings if she sold 46 bedcovers.

Solution:

We have,

Bonus if she sold 1 bedcover = Rs. Z

Bonus if she sold 46 bedcover = Rs. Z × 46

We know that,

Total earnings = Fixed salary + Bonus

                        = W+Z\times 46

Therefore, the correct option is (b).

3 0
1 year ago
My cupcake recipe makes $12$ cupcakes and requires $1\frac12$ sticks of butter. I can only buy whole sticks of butter. How many
andre [41]

Answer:

Given that,

My cupcake recipe makes $12$ cupcakes and requires $1\frac12$ sticks of butter. I can only buy whole sticks of butter.

Therefore, 1 whole sticks of butter is enough to make $100$ cupcakes.




8 0
2 years ago
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In a word processing document or on a separate piece of paper, use the guide to construct a two column proof proving that triang
Alex
I see the solution in three steps.
1.) RS ⊥ ST, RS ⊥ SQ, ∠STR ≅ ∠SQR | Given
2.) RS<span>≅RS | Reflexive Property
3.) </span><span>△RST ≅ △RSQ | AAS Triangle Congruence Property</span>
5 0
1 year ago
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Randy presses RAND on his calculator twice to obtain two random numbers between 0 and 1. Let $p$ be the probability that these t
anygoal [31]

Answer:

\frac{\pi}{4}

Step-by-step explanation:

Lets call x,y the numbers we obtain from the calculator. x and y are independent random variables of uniform[0,1] distribution.

Lets note that, since both x and y are between 0 and 1, then 1 is the biggest side of the triangle.

Lets first make a geometric interpretation. If the triangle were to be rectangle, then the side of lenght 1 should be its hypotenuse, and therefore x and y should satisfy this property:

x²+y² = 1

Remember that in this case we are supposing the triangle to be rectangle. But the exercise asks us to obtain an obtuse triangle. For that we will need to increase the angle obtained by the sides of lenght x and y. We can do that by 'expanding' the triangle, but if we do that preserving the values of x and y, then the side of lenght 1 should increase its lenght, which we dont want to. Thus, if we expand the triangle then we should also reduce the value of x and/or y so that the side of lenght 1 could preserve its lenght. With this intuition we could deduce that

x²+y² < 1

Now lets do a more mathematical approach. According to the Cosine theorem, a triangle of three sides of lenght a,b,c satisfies

a² = b²+c² - 2bc* cos(α), where α is the angle between the sides of lenght b and c.

Aplying this formula to our triangle, we have that

1^2 = x^2 + y^2 - 2bc* cos(\alpha) , where \alpha is the angle between the sides of lenght x and y.

Since the triangle is obtuse, then \pi/2 <  \alpha < \pi , and for those values cos(\alpha) is negative , hence we also obtain

1 > x² + y²

Thus, we need to calculate P(x²+y² <1). This probability can be calculated throught integration. We need to use polar coordinates.

(x, y) = (r*cosФ,r*senФ)

Where r is between 0 and 1, and Ф is between 0 and \pi /2 (that way, the numbers are positive).

The jacobian matrix has determinant r, therefore,

{\int\int}\limits_{x^2+y^2 < 1}  \, dxdy = \int\limits^1_0\int\limits^{\frac{\pi}{2}}_0 {r} \, d\phi dr = \frac{\pi}{2} * \int\limits^1_0 {r} \, dr =    \frac{\pi}{2} * (\frac{r^2}{2} |^1_0) = \frac{\pi}{4}

As a conclusion, the probability of obtaining an obtuse triangle is \frac{\pi}{4} .

6 0
2 years ago
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