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Nezavi [6.7K]
2 years ago
15

X - 4 = 10 A) x = 3 B) x = 6 C) x = 12 D) x = 14

Mathematics
2 answers:
hjlf2 years ago
7 0

x=14


Add 4 to both sides to isolate x

Tanzania [10]2 years ago
3 0

Answer:

D) x = 14

Step-by-step explanation:

X - 4 = 10

Add 4 to each side

x-4+4 = 10+4

x = 14

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Question 6 The mineral content of a particular brand of supplement pills is normally distributed with mean 490 mg and variance o
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Answer:

0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean 490 mg and variance of 400.

This means that \mu = 490, \sigma = \sqrt{400} = 20

What is the probability that a randomly selected pill contains at least 500 mg of minerals?

This is 1 subtracted by the p-value of Z when X = 500. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{500 - 490}{20}

Z = 0.5

Z = 0.5 has a p-value of 0.6915.

1 - 0.6915 = 0.3085

0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals

4 0
2 years ago
Bryce wrote the linear regression equation (Y=1.123x-6.443 to predict arm span,y,of a person who is x inches tall Riley has an a
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B) 65.84 add 67.5 and 6.443 and divide sum by 1.123
7 0
2 years ago
A randomized study compared two different systems for tracking baggage at an airport. The treatment group using System A reporte
Natasha2012 [34]

Answer:

D. The difference of the means is not significant because the re-randomizations show that it is within the range of what could happen by chance.

Step-by-step explanation:

The treatment group using System A reported a mean of 18.5 lost bags per day. The treatment group using System B reported a mean of 16.6 lost bags per day.

The best conclusion that can be made is - The difference of the means is not significant because the re-randomizations show that it is within the range of what could happen by chance.

As we know, in statistics, nothing happens by chance. So, this option is correct.

8 0
2 years ago
Read 2 more answers
At a grocery store, blueberries come packaged in 8-ounce containers for $2.80. At a farmer's market, blueberries cost $4.20 for
saveliy_v [14]
                            Grocery Store:                    Farmer's Market
Cost                        $2.80                                     $4.20
Weight                       8 oz                                       14 oz
Unit Cost
Cost ÷ Weight         $0.35 per oz                         $0.30 per oz
1 lb = 16 oz               16 oz                                      16 oz
Cost per pound       
Unit Cost * 16oz     $5.60 per lb                          $4.80 per lb

The blueberries in the farmer's market costs less than the blueberries from the grocery store. 

One pound of blueberries from the farmer's market is cheaper by $0.80 than the blueberries from the grocery store. ($5.60 - $4.80 = $0.80)
7 0
2 years ago
Read 2 more answers
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maks197457 [2]

Answer:  c)[50,60]

Step-by-step explanation:

The Empirical rule says that , About 68% of the population lies with the one standard deviation from the mean (For normally distribution).

We are given that , The heights of students in a class are normally distributed with mean 55 inches and standard deviation 5 inches.

Then by Empirical rule, about 68% of the heights of students lies between one standard deviation from mean.

i.e. about 68% of the heights of students lies between \text{Mean}\pm\text{Standard deviation}

i.e. about 68% of the heights of students lies between 55\pm5

Here, 55\pm5=(55-5, 55+5)=(50,60)

i.e.  The required interval that contains the middle 68% of the heights. = [50,60]

Hence, the correct answer is c) (50,60)

4 0
2 years ago
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