Answer:
The measure of Arc EH is 123°.
Step-by-step explanation:
Consider the diagram below.
It is provided that ∠EDH ≅ ∠EDG.
This implies that: ∠EDH = ∠EDG
The arc measure is same as the measure of the central angle.
That is:
arc FE = ∠EDF = 57°
arc FG = ∠FDG = 66°
Compute the measure of angle ∠EDH as follows:
arc EH = ∠EDH
=∠EDG
= ∠EDF + ∠FDG
= 57° + 66°
= 123°
Thus, the measure of Arc EH is 123°.
Since the range of the scores given was between 300 and 700 (which is 2 standard deviations below and above the mean), the probability that a randomly selected student's math score - as based on the empirical rule of statistics - is 95%. In decimal form, it is .95.
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SR = 450
<span>S = 450/R </span>
<span>(S - 3)(R + 5) = 450 </span>
<span>(450/R - 3)(R + 5) = 450 </span>
<span>(450 - 3R)(R + 5) = 450R </span>
<span>450R + 2250 - 3R^2 - 15R = 450R </span>
<span>3R^2 + 15R - 2250 = 0 </span>
<span>R^2 + 5R - 750 = 0 </span>
<span>R^2 + 30R - 25R - 750 = 0 </span>
<span>R(R + 30) - 25(R + 30) = 0 </span>
<span>(R + 30)(R - 25) = 0 </span>
<span>R ∈ {-30,25}
</span>
<span>Only positive numbers make sense in this context, therefore R = 25.</span>
5 19 6 -18
-3
-15 -12 18
5 4 -6 0
Therefore, the width is 5x^2 + 4x - 6
