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2 years ago

5

While remodeling her kitchen Angela is repainting. She estimates that she paints 55 square feet every half-hour. How many square

feet does Angela paint per hour?

1 answer:

madreJ [45]2 years ago

5 0

110 square feet. 55x2=100

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Expand and simplify (k-3)^7

nikklg [1K]

There are a couple of ways you can solve this. You can write it out like
(K-3)(K-3)(K-3)(K-3)(K-3)(K-3)(K-3)
And pretty much use the foil method
Or you can use the binomial theorem (google it if you dont know)
The solution should be:
(K^7) - 21(k^6) + 189(k^5) - 945(k^4) + 2835(k^3) - 5103(k^2) + 5103k - 2187

3 0

2 years ago

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A farmer plants corn in 1/4 of his field. He plants white corn in 3/5 of the corn

bija089 [108]

Answer:

$\frac{3}{20}$

Step-by-step explanation:

Fraction of the total that is for corn (TC - Total corn):

$TC=\frac{1}{4}$

fraction of the corn section that is for white corn (WC - white corn in the corn seccion):

$WC=\frac{3}{5}$

we need to find the fraction of the whole field that is for the white corn.

For this we need to find how much is $\frac{3}{5}$ out of the $\frac{1}{4}$ destinated to corn, and this will be the fraction of the total that is for white corn. We find this fraction by multiplying the fraction of corn ( $\frac{1}{4}$ ) by the fraction of white corn in the corn section ( $\frac{3}{5}$ ).

I will call the total fraction of white corn TWC, thus:

$TWC=WC*TC=\\=\frac{3}{5} *\frac{1}{4} \\\\=\frac{3*1}{5*4} \\\\=\frac{3}{20}$

the answer is: $\frac{3}{20}$ of the whole field is planted with white corn

5 0

2 years ago

Brenda is rolling a six-sided die and flipping a coin. Complete each of the following sentences regarding the probabilities invo

sveta [45]

So for number there are 6 possible outcomes nad 5 is one of them so 1/6
He next one there are 2 outcomes and heads is 1 outcome so 1/2
For the next one you have to multiply them together so you get 1/12
And the events are independent because whatever you roll on the die won’t affect the coin(it actually does on a very small scale but I don’t think you go into that much detail for high school maths)

8 0

2 years ago

Laila wants to create a data display to clearly show the median salary, the highest salary,

deff fn [24]

Answer:

a box plot

Step-by-step explanation:

Given the number of employees at her company is 685

If she chooses to create a dot plot, it means that she need to draw a lot, the total number of dots is 685 and even a wide domain of the number of data values on the x-axis.

If she chooses the box lot, which means that she wants to displays the five-number summary of a set of data. The five-number summary is the minimum, first quartile, median, third quartile, and maximum.

=> So it is the best fit for her choice.

If she chooses histogram, it means that she wants to group numbers into ranges to identify the underlying frequency distribution (shape) of a set of continuous data

Hope it will find you well

7 0

2 years ago

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If 8 identical blackboards are to be divided among 4 schools,how many divisions are possible? How many, if each school mustrecei

MAXImum [283]

Answer:

There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.

Step-by-step explanation:

Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.

The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is ${11 \choose 3} = 165 .$ As a result, we have 165 ways to distribute the blackboards.

If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is ${7 \choose 3} = 35$ . Thus, there are only 35 ways to distribute the blackboards in this case.

4 0

2 years ago