Brenda is rolling a six-sided die and flipping a coin. Complete each of the following sentences regarding the probabilities invo
1 answer:
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Diagram for part A and part C is attached herewith.
Solving for part B:-
Given is the circle O. We start with drawing two radii OA and OC, then we join two points A and C to make a chord AC of the circle. Now The radius of the circle intersects the chord AC at point B such that it bisects AC into two equal parts AB and BC. Now we have two triangles ΔOBA and ΔOBC. In these two triangles, we have OA=OC (radii of circle), OB=OB (reflexive property), and BA=BC (given in the question). Using SSS congruency of triangles we can say ΔOBA≡ΔOBC and using CPCTC, we can conclude ∡OBA=∡OBC (=90°). Hence OB⊥AC i.e. OB is perpendicular to AC.
Solving for part D:-
Given is the circle O. We start with drawing two radii OA and OC, then we join two points A and C to make a chord AC of the circle. Now The radius of the circle intersects the chord AC at point B such that AB is perpendicular to AC i.e. ∡B=90°. Now we have two Right triangles ΔOBA and ΔOBC. In these two triangles, we have OA=OC (radii of circle), OB=OB (reflexive property). Using HL congruency of right triangles we can say ΔOBA≡ΔOBC and using CPCTC, we can conclude BA=BC. Hence OB bisects AC into AB=BC.
Answer:
The answer is "GK=37, GH=14, and JK=19 ".
Step-by-step explanation:
In the question, an attachment file is missing.so, please find its attached file.
Given values:
GJ=4x+2
HK=6x-1
GK =37
Find:
HJ=?
GK = GJ+JK
= GJ+(HK-HJ)
= 4x+2+((6x-1)-x)
= 4x+2+6x-1-x
=
9x+1...(a)
Solve equation (a) and put the value of x in the equation:
=9(4)+1
=36+1
=37
find GH and JK=?
Given:
GK=37
Formula:
GH = GJ-HJ
= 4x+2- x
= 3x+2....(b)
Solve equation (a):
GK= 9x+1
37=9x+1
36=9x
x=4....(c)
put the value of equation (b) in equation (c)
GH = 3x+2
= 3(4)+2
= 12+2
= 14
Formula:
JK= HK-HJ
= 6x-1- x
= 5x-1
put the value of x in the above equation:
= 5(4)-1
= 20-1
=19
