The paraboloid meets the x-y plane when x²+y²=9. A circle of radius 3, centre origin.
<span>Use cylindrical coordinates (r,θ,z) so paraboloid becomes z = 9−r² and f = 5r²z. </span>
<span>If F is the mean of f over the region R then F ∫ (R)dV = ∫ (R)fdV </span>
<span>∫ (R)dV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] rdrdθdz </span>
<span>= ∫∫ [θ=0,2π, r=0,3] r(9−r²)drdθ = ∫ [θ=0,2π] { (9/2)3² − (1/4)3⁴} dθ = 81π/2 </span>
<span>∫ (R)fdV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] 5r²z.rdrdθdz </span>
<span>= 5∫∫ [θ=0,2π, r=0,3] ½r³{ (9−r²)² − 0 } drdθ </span>
<span>= (5/2)∫∫ [θ=0,2π, r=0,3] { 81r³ − 18r⁵ + r⁷} drdθ </span>
<span>= (5/2)∫ [θ=0,2π] { (81/4)3⁴− (3)3⁶+ (1/8)3⁸} dθ = 10935π/8 </span>
<span>∴ F = 10935π/8 ÷ 81π/2 = 135/4</span>
This is how the chart will look like:
Kermit Leonard Marlene Norma
Atley
Bradley
Cursen
Drake
1. Drake is Bradley's sister.
2. Cursen is Atley's brother
3. Norma and Drake are not related
<span>4. Kermit is a year older than Bradley
</span>
Drake is a girl (1), but she is not related to Norma(3), So she is Marlene.
1) MARLENE DRAKE
Drake and Bradley are related; Norma is not related to them(3). Norma can either be Atley or Cursen. But, Cursen is Male. So, Norma is NORMA ATLEY
Remaining family names are Bradley and Cursen. Kermit is not a Bradley, so he is KERMIT CURSEN. That leaves LEONARD BRADLEY.
I believe the answer is 3/8. The whole portion of employees, which is translated as 8/8 is deducted by 5/8, which is the population of male employees.
Animal shelter in Austin is a dog is 11.71% and <span>a randomly selected orphaned dog in the same animal shelter in Austin is a Chihuahua is</span> 29.38%.
