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2 years ago

Which of the following are exterior angles? Check all that apply.

Mathematics

2 answers:

victus00 [196]2 years ago

8 0

Answer:

B) ∠ 5

C) ∠ 4

F) ∠ 6

Step-by-step explanation:

you can mark the other user brainliest

Andre45 [30]2 years ago

5 0

B , C, F are the answers

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In a golf tournament, Sam played 4 rounds and was within 2 strokes of par for all 4 rounds of the tournament. If par is 72 on th

In-s [12.5K]

Given:

$|x-4(72)|=2$

To find:

The highest and lowest scores Sam could have made in the tournament.

Solution:

We have,

$|x-4(72)|=2$

$|x-288|=2$

It can be written as

$x-288=\pm 2$

Add 288 on both sides.

$x=288\pm 2$

$x=288-2$ and $x=288+2$

$x=286$ and $x=290$

Therefore, the highest and lowest scores Sam could have made in the tournament are 290 and 286 respectively.

8 0

2 years ago

PLEASE help!!!! Jackie runs and dances for a total of 55 minutes every day. She dances 25 minutes more than she runs. Part A: Wr

Andrew [12]

Part a:

x + y = 55

y = x + 25

part b:

jackie runs 15 minutes every day.

part c:

it is not possible for jackie to spend 45 minutes a day dancing, since the time she spends dancing and running is 55 minutes, and we know that it takes 15 minutes to run

step-by-step explanation:

let's call and while jackie is dancing

let's call x while jackie is running

then we know that jackie runs and dances for a total of 55 minutes every day

this means that:

x + y = 55

we also know that jackie dances 25 minutes more than she runs.

this meant that:

y = x + 25

now we substitute the second equation in the first and solve for the variable x

x + x + 25 = 552x = 55-252x = 30x = 15

jackie runs 15 minutes every day.

now we find the value of the variable -y

15 + y = 55y = 55-15y = 40

note that it is not possible for jackie to spend 45 minutes a day dancing, since the time she spends dancing and running is 55 minutes, and we know that it takes 15 minutes to run

7 0

2 years ago

Read 2 more answers

If the test scores of a class of 35 students have a mean of 74.3 and the test scores of another class of 28 students have a mean

STALIN [3.7K]

Let the total sum of the scores of the first class of 35 students be a. The mean is 74.3 .

So
$\frac{a}{35}=74.3\\\\a=35\cdot74.3= 2600.5$

Also, let the total sum of the scores of the second class of 28 students be b. The mean is 67.6 .

so
$\frac{b}{28}=67.6\\\\ b=28\cdot67.6= 1892.8$

The combined group has 35+28=63 students. The sum of their scores is

a+b=2600.5+1892.8=4493.3

Thus, the mean of the combined group is $\frac{4493.3}{63}= 71.32$

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2 years ago

The cross section of a parabolic reflector has a vertical axis of symmetry with its vertex at (0,0). The focus of the reflector

sattari [20]

Answer:

1.26 feets

Step-by-step explanation:

Given the following :

Vertex (0, 0)

Focus of reflector = 6 feets

Extension = 5.5 feets

Equation to obtain conic section of a parabola:

(x - h)² = 4p(y - k)

Vertex (0, 0)

h =0 ; k = 0, p = 6, x = 5.5

(5.5 - 0)² = 4*6(y - 0)

30.25 - 0 = 24(y - 0)

30.25 = 24y

y = 30.25 / 24

y = 1.26

Hence, depth of reflector = 1.26 feets

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2 years ago

Which statements are true? Check all that apply.

Sergio [31]

Answer:

1 The ratio of the measure of the central angle to the measure of the entire circle is StartFraction 5 Over 2 pi EndFraction

3 The area of the sector is 250 units².

5 The area of the sector is more than half of the circle’s area

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2 years ago

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