You are given two points on a line, and told that the function is "direct variation." You can save a lot of time by recognizing that the y-intercept here is zero (0). Thus, the line passes through the origin.
A line through (2,14) and (4,38) is NOT direct variation, because the line connecting those two points does NOT pass through the origin, and thus has a vertical intercept.
These are the <span>xx</span> and <span>yy</span> intercepts of the equation <span><span>2x−5y=6</span><span>2x-5y=6</span></span>.x-intercept: <span><span>(3,0)</span><span>(3,0)</span></span>y-intercept: <span>(0,−<span>65</span><span>)
</span></span>
2x + 2x +2 are the integers
4x^2 + 4x^2 +8x +4 =884 (The sum of the integers squared)
8 x^2 +8x -880 = 0
x = 10
Therefore, the integers are:
20 and 22
Partial derivative is derivative over only 1 variable.
here we have 2 variables so it depends on which variable you want to make partial derivative.
case 1.
df/dx = -3y
case 2
df/dy = 5y^4 - 3x
Answer:
Your answer should be AC=2DF=34
Step-by-step explanation:
