All categories

2 years ago

I NEED. HELP PLEASE, THANKS! :)

Mathematics

1 answer:

Nimfa-mama [501]2 years ago

3 0

Answer: A) 7 real zeros and 6 turning points at 0, 2, 4

Step-by-step explanation:

x⁷ - 6x⁶ + 8x⁵

The degree (largest exponent) is 7 so the maximum number of real zeros is 7.

Factor out x⁵

x⁵(x² - 6x + 8)

Factor the quadratic

x⁵(x - 2)(x - 4)

Set each factor equal to 0 and solve for x

x⁵ = 0 --> x = 0 (multiplicity of 5)

x - 2 = 0 --> x = 2

x - 4 = 0 --> x = 4

You might be interested in

Point of tangency of an inscribed circle divides a leg of an isosceles triangle into 3 cm and 4 cm line segments (considered fro

Lana71 [14]

Answer:

Step-by-step explanation:

5 0

2 years ago

Jamal works in a city and sometimes takes a taxi to work. The taxicabs charge $1.50 for the first 1/5 mile and $0.25 for each ad

Natalija [7]

1.50+.25x=3.75
.25x=2.25
x=9
9/5+1/5=10/5
2 miles

4 0

2 years ago

Read 2 more answers

The area of a small pond is 78.5 yds. What is the diameter of the pond?

Zolol [24]

Answer:

Diameter of pound = 10 yd

Step-by-step explanation:

Given area of circular pond = 78.5 square yd

To find the diameter of the pond.

Solution:

The pond being circular in shape, the area of pond can be given as:

⇒ $\pi\ r^2$

where $r$ represents radius of the pond.

Thus, we have:

⇒ $\pi\ r^2=78.5$

Using $\pi=3.14$

⇒ $3.14r^2=78.5$

Solving for $r$

Dividing both sides by 3.14

⇒ $\frac{3.14r^2}{3.14}=\frac{78.5}{3.14}$

⇒ $r^2=25$

Taking square root both sides.

⇒ $\sqrt{r^2}=\sqrt{25}$

⇒ $r=\pm5$

So, radius = 5 yd, as distances are always positive.

Diameter = $2\times radius=2\times 5\ yd= 10\ yd$

Thus, diameter of pound = 10 yd

7 0

2 years ago

Multiplying StartFraction 3 Over StartRoot 17 EndRoot minus StartRoot 2 EndRoot EndFraction by which fraction will produce an eq

ziro4ka [17]

The fraction which produce an equivalent fraction with a rational denominator is $\left(\frac{\sqrt{17}+\sqrt{2}}{\sqrt{17}+\sqrt{2}}\right)$

Explanation:

The equation is $\frac{3}{\sqrt{17}-\sqrt{2}}$

To find the rational denominator, let us take conjugate of the denominator and multiply the conjugate with both numerator and denominator.

Rewriting the equation, we have,

$\frac{3}{\sqrt{17}-\sqrt{2}}\left(\frac{\sqrt{17}+\sqrt{2}}{\sqrt{17}+\sqrt{2}}\right)$

Multiplying, we get,

$\frac{3(\sqrt{17}+\sqrt{2})}{(\sqrt{17})^{2}-(\sqrt{2})^{2}}$

Simplifying the denominator, we get,

$\frac{3(\sqrt{17}+\sqrt{2})}{17-2}$

Subtracting, the values of denominator,

$\frac{3(\sqrt{17}+\sqrt{2})}{15}$

Dividing the numerator and denominator,

$\frac{\sqrt{17}+\sqrt{2}}{5}$

Hence, the denominator has become a rational denominator.

Thus, the fraction which produce an equivalent fraction with a rational denominator is $\left(\frac{\sqrt{17}+\sqrt{2}}{\sqrt{17}+\sqrt{2}}\right)$

6 0

2 years ago

Read 2 more answers

A car dealership has 24 feet of dividers with which to enclose a rectangular play space in a corner

blondinia [14]

Answer:Answer:a) Area=f(x)= 24x-x^2

b) f(x) ranges from 0 to 144

c) Area max = 144 ft^2

Step-by-step explanation: shown in the attachment

7 0

2 years ago