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Scorpion4ik [409]
1 year ago
12

If m < apd =109 and m <1=17 then m<bpd=

Mathematics
1 answer:
just olya [345]1 year ago
4 0

m < bpd = 349
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State the size of angle OAB, giving a reason for your answer
Alja [10]

Answer:

Angle OAB = 90°

Reason: tangent theorem of a circle

Step-by-step explanation:

The diagram given shows a tangent line of the given circle with center O. The tangent touches the circle at point A.

The diagram also shows the radius of the circle, OA, drawn from the center to the circle to meet at the point of tangency.

Thus, according to the Tangent Theorem of a circle, the point at which the radius drawn from the center meets the point of tangency = 90°. The tangent is perdendicular to the radius drawn to meet at the point of tangency.

Therefore, angle OAB = 90°

5 0
2 years ago
Bailey likes the shape of her friend's pool, but she wants one that is half the volume. According to Cavalieri’s Principle, what
Cerrena [4.2K]

Answer: I need a picture off the pool and measurements.

Step-by-step explanation: I need this in order to figure out the problem and give you a helpful answer.

8 0
2 years ago
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(p²qr + pq²r + pqr²)(-pq + qr - pr)<br>Please solve this problem as soon as possible.​
Marta_Voda [28]

Answer:

−p3q2r−p3qr2−p2q3r−p2q2r2−p2qr3+pq3r2+pq2r3

Step-by-step explanation:

(p2qr+pq2r+pqr2)((−p)(q)+qr+−pr)

(p2qr)((−p)(q))+(p2qr)(qr)+(p2qr)(−pr)+(pq2r)((−p)(q))+(pq2r)(qr)+(pq2r)(−pr)+(pqr2)((−p)(q))+(pqr2)(qr)+(pqr2)(−pr)

−p3q2r+p2q2r2−p3qr2−p2q3r+pq3r2−p2q2r2−p2q2r2+pq2r3−p2qr3

−p3q2r−p3qr2−p2q3r−p2q2r2−p2qr3+pq3r2+pq2r3

4 0
1 year ago
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The lithosphere (made of Earth's crust and the very top part of the mantle) is a stiff outer layer of the Earth. Convection in t
Ilya [14]
Convection in the <u>Mantle</u> helps move pieces of the lithosphere around.
6 0
2 years ago
A commercial jet can fly 868 miles in 2 hours with a tailwind but only 792 miles in 2 hours into a headwind. Find the speed of t
erik [133]

Answer:

The speed of the jet in still air is 415 mph and the speed of the wind is 19 mph

Step-by-step explanation:

we know that

The speed is equal to divide the distance by the time

Let

x -----> the speed of the wind in miles per hour

y ----> the speed of the jet in still air in miles per hour

we know that

<em>With a tailwind</em>

y+x=\frac{868}{2}

y+x=434 ----> equation A

<em>With a headwind</em>

y-x=\frac{792}{2}

y-x=396 ----> equation B

solve the system of equations A and B by elimination

Adds equation A and equation B

y+x=434\\y-x=396\\------\\y+y=434+396\\2y=830\\y=415

<em>Find the value of x</em>

y+x=434

415+x=434

x=434-415

x=19

therefore

The speed of the jet in still air is 415 mph and the speed of the wind is 19 mph

6 0
1 year ago
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