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storchak [24]
2 years ago
7

Which ordered pairs are in a proportional relationship with (0.2, 0.3)?

Mathematics
1 answer:
MAXImum [283]2 years ago
4 0

Answer:

C and E

Step-by-step explanation:

We are given that

x_1=0.2,y_1=0.3

\frac{y}{x}=\frac{0.3}{0.2}=\frac{3}{2}

k=\frac{y}{x}=\frac{3}{2}

A.x_2=1.2,y_2=2.3

\frac{y_2}{x_2}=\frac{2.3}{1.2}=\frac{23}{12}\neq=\frac{3}{2}

Hence, it is not in proportional relationship with (0.2,0.3)

B.(2.7,4.3)

x_3=2.7,y_3=4.3

\frac{y_3}{x_3}=\frac{4.3}{2.7}=\frac{43}{27}\neq\frac{3}{2}

Hence, it is not in proportional relationship with (0.2,0.3).

C.(3.2,4.8)

x_4=3.2,y_4=4.8

\frac{y_4}{x_4}=\frac{4.8}{3.2}=\frac{3}{2}

Hence, the ordered pair (3.2,4.8) are in a proportional relationship with (0.2,0.3).

D.(3.5,5.3)

\frac{y_5}{x_5}=\frac{5.3}{3.5}=\frac{53}{35}\neq \frac{3}{2}

Hence, the ordered pair (3.5,5.3) are not in a proportional relationship with (0.2,0.3).

E.(5.2,7.8)

\frac{y_6}{x_6}=\frac{7.8}{5.2}=\frac{3}{2}

Hence, the ordered pair (5.2,7.8) are in a proportional relationship with (0.2,0.3).

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The confidence interval for the difference in proportions is

-0.028\leq p_1-p_2 \leq 0.096

No. As the 95% CI include both negative and positive values, no proportion is significantly different from the other to conclude there is a difference between them.

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We have to construct a confidence interval for the difference of proportions.

The difference in the sample proportions is:

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The estimated standard error is:

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