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kotegsom [21]
2 years ago
6

A website has no more than $15,000 to give away for a contest. They have decided to give away $1,000 twice a day every day until

they have at least $3,000 left to award as a grand prize. How many days will the contest run?
Mathematics
1 answer:
vredina [299]2 years ago
7 0
If you would like to know how many days will the contest run, you can calculate this using the following steps:

x ... the number of days
every day: 2 * $1,000 = $2,000
$15,000 - $2,000 * x = $3,000
15,000 - 2,000 * x = 3,000
15,000 - 3,000 = 2,000 * x
12,000 = 2,000 * x
x = 12,000 / 2,000
x = 6 days

The correct result would be: The contest will run for 6 days until they have at least $3,000 left to award as a grand prize.
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Carl is paid an hourly rate of $12.65 what is his weekly gross pay if he works 25 hours per week?
san4es73 [151]
12.65x25= $316.25 (I think)
7 0
1 year ago
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The Greens want to put an addition on their house 18 months from now. They will need to save $10,620 in order to achieve this go
ValentinkaMS [17]
Option A. is the correct answer :)
4 0
2 years ago
Colin gets pic 'n mix when at the cinema and makes his bag up with 3 types of sweet. He pick:
Kisachek [45]

Answer: 2/3

Explanation: Assume that the number of smarties he picked is c.

Now, we are given that:

1- He picked 3 times as many cola bottles as smarties. This means that:

Number of cola bottles he picked = 3s

2- He picked twice as many smarties as marshmallows. This means that:

number of marshmallows he picked = 0.5s

Now to get the proportion o f cola bottles, we will divide the number of cola bottles by the total number of sweets as follows:

proportion of cola bottles =  

Hope this helps :)

4 0
1 year ago
A boy had 20 cents. He bought x pencils for 3 cents each. If y equals the number of pennies left, write an equation showing the
Vesna [10]

Hey there!!

The total number of cents - 20

Cost for each pencil - 3 cents

Number of pencils bought - ' x '

y = number of pennies left

What is the domain ?

Show how y is dependent on x ..

Let's get this into an equation :

... The total cost for x pencils bought = 3x

... Number of pennies left = 20 - 3x

... y = number of pennies left

... y = 20 - 3x

Notice : If the x value changes, the y value changes too

... If x = 1 , then , y = 17; If x = 2 , then , y = 14

Hence, we could say y is dependent upon x

Domain = ?

... Remember - The total number of pennies = 20 ; hence, the total cost cannot go above 20 cents.

Hence, we will have to work with inequalities

The equation  :

... 20 ≥ 3x

Divide 3 on both sides

20 / 3 ≥ x

x ≥ 6.667

Let's take this as 6

Hence , the domain will be :

D : { 1 , 2 , 3 , 4 , 5 , 6 }

Hope my answer helps!

6 0
2 years ago
La fuerza necesaria para evitar que un auto derrape en una curva varía inversamente al radio de la curva y conjuntamente con el
Vika [28.1K]

Answer:

768 libras de fuerza

Step-by-step explanation:

Tenemos que encontrar la ecuación que los relacione.

F = Fuerza necesaria para evitar que el automóvil patine

r = radio de la curva

w = peso del coche

s = velocidad de los coches

En la pregunta se nos dice:

La fuerza requerida para evitar que un automóvil patine alrededor de una curva varía inversamente con el radio de la curva.

F ∝ 1 / r

Y luego con el peso del auto

F ∝ w

Y el cuadrado de la velocidad del coche

F ∝ s²

Combinando las tres variaciones juntas,

F ∝ 1 / r ∝ w ∝ s²

k = constante de proporcionalidad, por tanto:

F = k × w × s² / r

F = kws² / r

Paso 1

Encuentra k

En la pregunta, se nos dice:

Suponga que 400 libras de fuerza evitan que un automóvil de 1600 libras patine alrededor de una curva con un radio de 800 si viaja a 50 mph.

F = 400 libras

w = 1600 libras

r = 800

s = 50 mph

Tenga en cuenta que desde el

F = kws² / r

400 = k × 1600 × 50² / 800

400 = k × 5000

k = 400/5000

k = 2/25

Paso 2

¿Cuánta fuerza evitaría que el mismo automóvil patinara en una curva con un radio de 600 si viaja a 60 mph?

F = ?? libras

w = ya que es el mismo carro = 1600 libras

r = 600

s = 60 mph

F = kws² / r

k = 2/25

F = 2/25 × 1600 × 60² / 600

F = 768 libras

Por lo tanto, la cantidad de fuerza que evitaría que el mismo automóvil patine en una curva con un radio de 600 si viaja a 60 mph es de 768 libras.

7 0
2 years ago
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