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Pachacha [2.7K]
2 years ago
13

Which of these lists correctly orders the binary numbers from smallest to largest? Choose 1 answer: Choose 1 answer: (Choice A)

A 001100110011, 011001100110, 010101010101, 101010101010 (Choice B) B 001100110011, 010101010101, 011001100110, 101010101010 (Choice C) C 101010101010, 010101010101, 011001100110, 001100110011 (Choice D) D 101010101010, 011001100110, 010101010101, 00110011
Mathematics
1 answer:
aleksandr82 [10.1K]2 years ago
5 0
Try using photomath it will explain on what to do.
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A scatter plot containing the point (6, 8) has the regression equation yˆ=6x+4 . What is the residual e when x = 6?
Anna11 [10]

Residual is the difference between the y value of scatter plot and y value of regression equation

A scatter plot containing the point (6, 8), the y value of scatter plot is 8

y=6x+4, to get y value of regression equation we plug in 6 for x

y = 6(6) + 4 = 40

Residual e = y value of scatter plot - y value of regression equation

=8 - 40 = -32

Answer : e=-32




5 0
2 years ago
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JUST ONE MORE I NEED HELP ON HW IM STRUGGLING 15pts
Gemiola [76]

Answer:

y equals one fourth times x minus 16

y = 4x − 16

Step-by-step explanation:

this is because you're taking the time it took to get there minus 16 because of the delay

3 0
2 years ago
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Javier is comparing costs of two cars. Car A costs $130 per month for insurance and $0.10 per mile to run. Car B costs $108 per
nikklg [1K]
The answer is 130 + .10m = 108 + .15m
3 0
2 years ago
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If AD = 2/3 AB , what is the ratio of the length of arc BC to the length of arc DE
uysha [10]

You have :

--------------

DE arc = ( pi ) ( AD ) ( 2.36 radians / 2 pi radians ) = ( 2/3 ) ( AB ) ( 2.36 radians / 2 )

DE arc = ( 2/3 ( AB ) ( 1.18 radians )

BC arc = ( pi ) ( AB ) ( 1.18 radians / 2 pi radians )

BC arc = ( AB ) ( 0.59 radians )

BC arc / DE arc = ( AB ) ( 0.59 radians ) / ( 2/3 ) ( AB ) ( 1.18 radians )

BC arc / DE arc = ( AB ) ( 0.59 rad ) / ( 2/3 ) ( AB ) ( 1.18 rad )

BC arc / DE arc = ( 3/2 ) ( .59 rad / 1.18 rad ) = 3/4 <-------

6 0
2 years ago
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Suppose that the probability density function for the length x in feet of some type of fish caught by sport fishermen is given b
Firdavs [7]

Answer:

The probability that a fish caught by a fisherman is between 0.25 feet and 2 feet long is 0.4375.

Step-by-step explanation:

The probability density function or p.d.f. for the length <em>x,</em> in feet, of some type of fish caught by sport fishermen is :

p(x) = \left \{{{(\frac{1}{4})\ ;\  0\leq x\leq 4 } \atop{0\ ;\ otherwise} \right.

The probability that a fish caught by a fisherman is between 0.25 feet and 2 feet long is:

P(0.25\leq X\leq 2)=\int\limits^{0.25}_{2} {(\frac{1}{4})} \, dx \\=|(\frac{1}{4})x|^{2}_{0.25}\\=(\frac{1}{4})(2-0.25)\\=0.4375

Thus, the probability that a fish caught by a fisherman is between 0.25 feet and 2 feet long is 0.4375.

8 0
2 years ago
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