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Kobotan [32]
1 year ago
13

The data set below represents the total number of touchdowns a quarterback threw each season for 10 seasons of play.

Mathematics
2 answers:
tia_tia [17]1 year ago
7 0

The range is  24  touchdowns.

The interquartile range is  8  touchdowns.

Leona [35]1 year ago
5 0
Here are your measures of variability. The range is found by subtracting the highest and the lowest (29-5=24). To find the interquartile range, you will find the median of the lower half of the data and the median of the higher half of sta and subtract these 2 numbers. Here is your list. I have PUT PARENTHESES around the upper and lower quartiles: 5, 17, (18), 20, 20, 21, 23, (26), 28, 29. It is like finding the middle of the entire set of data and then finding the middle of each half. Subtract 26 and 18 to find the interquartile range of 8 touchdowns.
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You have five pieces of wood. The lengths of these are shown below.
Deffense [45]

Answer:

1,249 cm or 12.49

Whichever one it asks for

Step-by-step explanation:

First, we need to convert all of the m to cm.

4.04 m = 404 cm

1.6 m = 160 cm

2.87 m = 287 cm

Next, add them all up.

325 + 404 + 73 + 160 + 287 =

1,249 cm

If it asks to convert to m again, then the answer would be 12.49 m

Hope this helps!!!

3 0
1 year ago
Read 2 more answers
I talk to an average of 8 customers per hour during an 8 hour shift and need to increase the amount of customers i help by 20%,
lbvjy [14]

Answer:

The number of customer needed to achieve is 34

Step-by-step explanation:

Given as :

The number of customer per hour = 8

The time taken = 8 hours

The rate of increase = 20 %

Let The increase in number of customer after 20 % increment = x

So ,  The number of customer after n hours = initial number × (1+\dfrac{\textrm rate}{100})^{n}

or, The number of customer after 8 hours = 8 ×  (1+\dfrac{\textrm 20}{100})^{8}

or, The number of customer after 8 hours = 8 × 4.2998

∴The number of customer after 8 hours = 34.39 ≈ 34

Hence The number of customer needed to achieve is 34  answer

8 0
2 years ago
Tesla wanted to determine the average miles per kWh that their vehicles get across all models and variations. They took a sample
LiRa [457]

Answer:

\mu_{\bar x} = \mu = E(X) =30KWh

\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}=\frac{3}{\sqrt{100}}=0.3

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

For this case we select a sample of n =100

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

So then the sample mean would be:

\mu_{\bar x} = \mu = E(X) =30KWh

And the standard deviation would be:

\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}=\frac{3}{\sqrt{100}}=0.3

6 0
1 year ago
A manager associated each employee's name with a number on one ball in a container, then drew balls without looking to select a
RUDIKE [14]
Answer: This type of sampling is Simple Random Sampling
7 0
2 years ago
Read 2 more answers
Photon Lighting Company determines that the supply and demand functions for its most popular lamp are as follows: S(p) = 400 - 4
BlackZzzverrR [31]
S(p) = 400 - 4p + 0.00002p^4
D(p) = 2800 - 0.0012p^3

S(p) = D(p)
400 - 4p + 0.00002p^4 = 2800 - 0.0012p^3
0.00002p^4 + 0.0012p^3 - 4p - 2400 = 0
p = $96.24
6 0
1 year ago
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