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Kobotan [32]
2 years ago
13

The data set below represents the total number of touchdowns a quarterback threw each season for 10 seasons of play.

Mathematics
2 answers:
tia_tia [17]2 years ago
7 0

The range is  24  touchdowns.

The interquartile range is  8  touchdowns.

Leona [35]2 years ago
5 0
Here are your measures of variability. The range is found by subtracting the highest and the lowest (29-5=24). To find the interquartile range, you will find the median of the lower half of the data and the median of the higher half of sta and subtract these 2 numbers. Here is your list. I have PUT PARENTHESES around the upper and lower quartiles: 5, 17, (18), 20, 20, 21, 23, (26), 28, 29. It is like finding the middle of the entire set of data and then finding the middle of each half. Subtract 26 and 18 to find the interquartile range of 8 touchdowns.
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Consider the table showing the given, predicted and residual values for a data set. A 4-column table with 4 rows. The first colu
Alecsey [184]

Answer:

Step-by-step explanation: I believe the answer would be (4, 0.1).

When plotting a residual, use the x-value, in this case 4, and the residual value as the y. (4, 0.1) The 4 is the x value, and the 0.1 replaces the y value. In the table the column headers will show you what the x, y, and residuals are. Just disregard the y-value and "predicted" and "given" columns, they are not needed when plotting the residual. I really hope this helps, and I hope I explained it well!

5 0
2 years ago
Read 2 more answers
The championship record in baseball in a certain year was 52 games won, and 14 lost. What percent of the games were won?
slamgirl [31]
Number of games won/Number of total games played x 100%

52/66 x 100% = 78.79%

Hope u understood! :)
5 0
2 years ago
Charlie is watching hot air balloons. Balloon A has risen at a 56° angle. Balloon B has risen at an 81° angle. If the distance f
sweet [91]

Answer:

999 ft

Step-by-step explanation:

In the picture attached, the drawn of the situation is shown

<u>Data</u>

  • ∠x = 56°
  • ∠y = 81°
  • distance from balloon A to the ground is 1,200 feet

From definition:

tan(∠x) = opposite/adjacent

tan(56°) = 1200/adjacent

adjacent to ∠x = 1200/tan(56°)

adjacent to ∠x = 809.41 ft

tan(∠y) = opposite/adjacent

tan(81°) = 1200/adjacent

adjacent to ∠y = 1200/tan(81°)

adjacent to ∠y = 190.06 ft

The distance from balloon A to balloon B is: 809.41 + 190.06 = 999.47 ≈ 999 ft

8 0
1 year ago
Read 2 more answers
In a test, the total of the marks scored by Sampat and Ganpat was 125% more than Sampat's
lord [1]
The difference in the their marks is 20%
4 0
1 year ago
Susan keeps track of the number of tickets sold for each play presented at the community theater. within how many standard devia
Citrus2011 [14]
The Mean = (135 + 71 + 69 + 80 + 158 + 152 + 161 + 96 + 122 + 118 + 87 + 85 ) : 12 = 111.166
The smallest value : 69
The greatest value : 161
s² = ∑( x i - x )² / ( n - 1 )
s² = ( 568.274 + 1613.3 + 1777.97 + 971.32 + 2193.42 + 1667.4 + +2483.42 + 230 + 117.38 + 46.7 + 584 + 684.66 )  : 11
s² = 1176.1676
s = √s² = √1176.1676
s ( Standard deviation ) = 34.295
All the values fall within 2 standard deviations:
 x (Mean) - 2 s and  x + 2 s 
 
3 0
1 year ago
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