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2 years ago

Which could be the entire interval over which the function, f(x), is negative?

Mathematics

2 answers:

lana [24]2 years ago

6 0

For this case we have a function of the form:

y = f (x)

Where,

x: independent variable

y: dependent variable

To answer the question, we must see in the table the values of the independent variable x, for which the values of the dependent variable f (x) are negative.

We have then that the interval that fulfills this condition is from minus infinity to minus 4 without including the 4.

Thus,

(–∞, –4)

Answer:

The entire interval over which the function, f(x), is negative is:

D) (–∞, –4)

GaryK [48]2 years ago

6 0

The answer is D I just took the test 100% right

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Suppose that the probability density function for the length x in feet of some type of fish caught by sport fishermen is given b

Firdavs [7]

Answer:

The probability that a fish caught by a fisherman is between 0.25 feet and 2 feet long is 0.4375.

Step-by-step explanation:

The probability density function or p.d.f. for the length <em>x,</em> in feet, of some type of fish caught by sport fishermen is :

$p(x) = \left \{{{(\frac{1}{4})\ ;\ 0\leq x\leq 4 } \atop{0\ ;\ otherwise} \right.$

The probability that a fish caught by a fisherman is between 0.25 feet and 2 feet long is:

$P(0.25\leq X\leq 2)=\int\limits^{0.25}_{2} {(\frac{1}{4})} \, dx \\=|(\frac{1}{4})x|^{2}_{0.25}\\=(\frac{1}{4})(2-0.25)\\=0.4375$

Thus, the probability that a fish caught by a fisherman is between 0.25 feet and 2 feet long is 0.4375.

8 0

2 years ago

Select all the properties that are used below to solve 7y − 15 = −29. 7y – 15 + 15 = –29 + 15 7y = –14 7y7 = –147 y = –2 A. Iden

lukranit [14]

B.addition property of multiplication

D.inverse property of multiplication

E.commutative property of addition

3 0

2 years ago

Bogle Company purchased machinery for $320,000 on January 1, 2014. Straight-line depreciation has been recorded based on a $20,0

horrorfan [7]

Answer:

$66,000

Step-by-step explanation:

Data provided in the question:

Purchasing cost of the machine = $320,000

Salvage value = $20,000

Useful life of the machine = 5 years

The gain on selling of the machine = $6,000

Now,

The annual depreciation of the machine

= [Cost - salvage value] ÷ ( Useful life )

= [ $320,000 - $20,000 ] ÷ 5

= $60,000

Accumulated depreciation from January 1, 2014 to May 1, 2018

= Annual depreciation × (Duration from January 1, 2014 to May 1, 2018 )

= $60,000 × ( 4 years 4 months )

= $60,000 × $\frac{52}{12}$ years

[48 months + 4 months = 52 months]

= $260,000

Therefore,

Book value on May 1, 2018 = Cost - Accumulated depreciation

= $320,000 - $260,000

= $60,000

Now,

Gain = Selling cost - Book value

$6,000 = Selling cost - $60,000

Selling cost = $66,000

Hence,

cash Bogle received from the sale of the machinery was $66,000

7 0

2 years ago

When Ryan is serving at a restaurant, there is a 0.75 probability that each party will order drinks with their meal. During one

Triss [41]

Answer:

0.82 = 82% probability that at least one party will not order drinks

Step-by-step explanation:

For each party, there are only two possible outcomes. Either they will order drinks with their meal, or they will not. The probability of a party ordering drinks with their meal is independent of other parties. So the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

When Ryan is serving at a restaurant, there is a 0.75 probability that each party will order drinks with their meal.

This means that $p = 0.75$

During one hour, Ryan served 6 parties. Assuming that each party is equally likely to order drinks, what is the probability that at least one party will not order drinks?

6 parties, so n = 6.

Either all parties will order drinks, or at least one will not. The sum of the probabilities of these events is decimal 1. So

$P(X = 6) + P(X < 6) = 1$

We want P(X < 6). So

$P(X < 6) = 1 - P(X = 6)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{6,6}.(0.75)^{6}.(0.25)^{0} = 0.18$

$P(X < 6) = 1 - P(X = 6) = 1 - 0.18 = 0.82$

0.82 = 82% probability that at least one party will not order drinks

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2 years ago

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