The table shows the results of (p ^ q) and results of (p ^ r) for all possible outcomes. We have to tell which of the outcomes of union of both these events will always be true.
(p ^ q) V (p ^ r) means Union of (p ^ q) and (p ^ r). The property of Union of two sets/events is that it will be true if either one of the event or both the events are true i.e. there must be atleast one True(T) to make the Union of two sets to be True.
So, (p ^ q) V (p ^ r) will be TRUE, if either one of (p ^ q) and (p ^ r) or both are true. From the given table we can see that only the outcomes A, B and C will result is TRUE. The rest of the outcomes will all result in FALSE.
Therefore, the answer to this question is option 2nd
Answer:
6, 6w, 3w, z and w.
Step-by-step explanation:
The common factors are those values that can divide 18w and 30wz perfectly.
Take a look at 6, 6 can divide both perfectly to give 3w and 5wz respectively.
We move on to 6w, this can also work perfectly to yield 3 and 5z.
6xz is not a factor as both values do not contain any x term.
3z is not a factor. Although 30wz has a z term, 18w does not.
3w is a factor as it can give 10z and 6 when used to divide the terms.
Z is not a factor as the 18w term does not contain a z term.
10w is not a term as it can not divide 18w perfectly
w is a term as it can divide both 18w and 30wz perfectly to yield 18 and 30z respectively.
First thing to do is to remember, that the circumference of the full circle is 2(6)pi--12pi. you only want about 120 of it so (120/360)=1/3, so you add it into the thing earlier to get, 12pi(1/3)=4pi =12.566... which you can round into 12.6. This is answer choice A.
Answer:
Step-by-step explanation:
The description is too ambiguous to reconstruct the diagram. You need to post the actual diagram.
That diagram is just one way to view division by a fraction. An easier way: DIVIDING by a fraction is the same as MULTIPLYING by the upside-down fraction. For example,
(1/2) ÷ (1/4) = (1/2) × (4/1) = 2
That doesn’t help you answer this particular question, though.