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1 year ago

8

The graph shows the function f(x) = (2.5)x was horizontally translated left by a value of h to get the function g(x) = (2.5)x–h.

On a coordinate plane, 2 exponential functions are shown. f (x) approaches y = 0 in quadrant 2 and increases into quadrant 1. It goes through (negative 1, 0.5) and crosses the y-axis at (0, 1). g (x) approaches y = 0 in quadrant 2 and increases into quadrant 1. It goes through (negative 2, 1) and crosses the y-axis at (0, 6). What is the value of h? Group of answer choices 1/2 5 -2 0

2 answers:

ziro4ka [17]1 year ago

8 0

Answer:

-2

Step-by-step explanation:

aniked [119]1 year ago

4 0

Answer:

-2

Step-by-step explanation:

ed2021

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Determine the product: (46.2 × 10–1) ⋅ (5.7 × 10–6). Write your answer in scientific notation.

lianna [129]

Answer:

A

Step-by-step explanation:

10-6 X 10-1 = 10-7

5.7*46.2=263.34

263.34=2.6334 x 10^2

10^2 x 10^-7 = 10^-5

so

=2.6334 x 10-5

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2 years ago

Just need to check these answers

amid [387]

Great Job! they are all correct. :)

Good luck in your next tests.

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2 years ago

For every $10 Glen earns, his parents

irga5000 [103]

10-2 = 8

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1 year ago

Read 2 more answers

A pebble is tossed into the air from the top of a cliff. The height, in feet, of the pebble over time is modeled by the equation

Charra [1.4K]

Answer:

96

Step-by-step explanation:

The maximum height reached by the pebble modeled by the quadratic function,

$h(t)=-16t^2+32t+80$ , can be found by finding the vertex.

Let's first find the t-coordinate of the vertex . The max height will correspond to this value of t which means we have to find the h(t)-coordinate.

When comparing $h$ to $at^2+bt+c$ , we see that:

$a=-16$

$b=32$

$c=80$

We need to evaluate the following to find the t-coordinate of the vertex:

$t=\frac{-b}{2a}$

$t=\frac{-32}{2(-16)}$

$t=\frac{-32}{-32}$

$t=1$

So now to find the correspond h(t)-coordinate, we will need to replace t in $-16t^2+32t+80$ with 1:

$-16(1)^2+32(1)+80$

$-16(1)+32+80$

$-16+32+80$

$16+80$

$96$

5 0

2 years ago

Suppose that you want to estimate the mean pH of rainfalls in an area that suffers from heavy pollution due to the discharge of

labwork [276]

Answer:

The number of rainfalls is $n =96$

The answer to the second question is no it will not be valid this because from the question we are told that the experiment require one pH reading per rainfall so getting multiply specimens(used for the pH reading) from one rainfall will make the experiment invalid.

Step-by-step explanation:

from the question we are told that

The standard deviation is $\sigma = 0.5$

The margin of error is $E = 0.1$

Given that the confidence level is 95% then we can evaluate the level of significance as

$\alpha = 100 - 95$

$\alpha = 5 \%$

$\alpha =0.05$

Next we will obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table , the value is $Z_{\frac{\alpha }{2} } = 1.96$

Generally the sample size is mathematically represented as

$n = [\frac{Z_{\frac{\alpha }{2} * \sigma }}{ E} ]^2$

substituting values

$n = [\frac{1.96 * 0.5 }{ 0.1} ]^2$

$n =96$

The answer to the second question is no the validity is null this because from the question we are told that the experiment require one pH reading per rainfall so getting multiply specimens(used for the pH reading) from one rainfall will make the experiment invalid

5 0

2 years ago