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nadya68 [22]
2 years ago
12

Mathew got 20 pencils, 3 rulers, 12 erasers,11 pens, 24 notebooks, 8 files, and 11 paper clips from a stationery shop for his br

other
Mathematics
1 answer:
Damm [24]2 years ago
3 0

Answer:

89

Step-by-step explanation:He bought 89 items because 20 + 3 is 23, 23 + 12 is 35, 35 + 11 is 46, 46 + 24 is 70, and 70 + 11 is 89.

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The cost of a parking permit consists of a one-time administration fee plus a monthly fee. A permit purchased for 12 months cost
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The answer is 60 dollars
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The following Venn Diagram shows the results of a teacher survey. A teacher asked her class which students owned android phones,
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Answer: 0.60

Step-by-step explanation:

30 total students

6 have Androids

6+2+4= 12 had services with AT&T

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0.60 when you divide 3 into 5

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A lab technician is tested for her consistency by making multiple measurements of the cholesterol level in one blood sample. The
Zanzabum

Step-by-step explanation:

Given precision is a standard deviation of s=1.8, n=12,  target precision is a standard deviation of σ=1.2

The test hypothesis is

H_o:σ <=1.2

Ha:σ > 1.2

The test statistic is

chi square = \frac{(n-1)s^2}{\sigma^2}

=\frac{(12-1)1.8^2}{1.2^2}

=24.75

Given a=0.01, the critical value is chi square(with a=0.01, d_f=n-1=11)= 3.05 (check chi square table)

Since 24.75 > 3.05, we reject H_o.

So, we can conclude that her standard deviation is greater than the target.

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2 years ago
Roy's average balance checking account pays simple interest of 4.8% annually and he made $2.25 in interest last month. What was
Leona [35]

Answer:

It’s 5625.00 don’t listen to this other one

Step-by-step explanation:

5 0
2 years ago
A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The
Oksanka [162]

Answer:

a) [-0.134,0.034]

b) We are uncertain

c) It will change significantly

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a) Since the variances are unknown, we use the t-test with 95% confidence interval, that is the significance level = 1-0.05 = 0.025.

Since we assume that the variances are equal, we use the pooled variance given as

s_p^2 = \frac{ (n_1 -1)s_1^2 + (n_2-1)s_2^2}{n_1+n_2-2},

where n_1 = 40, n_2 = 30, s_1 = 0.16, s_2 = 0.19.

The mean difference \mu_1 - \mu_2 = 10.85 - 10.90 = -0.05.

The confidence interval is

(\mu_1 - \mu_2) \pm t_{n_1+n_2-2,\alpha/2} \sqrt{\frac{s_p^2}{n_1} + \frac{s_p^2}{n_2}} = (-0.05) \pm t_{68,0.025} \sqrt{\frac{0.03}{40} + \frac{0.03}{30}}

= -0.05\pm 1.995 \times 0.042 = -0.05 \pm 0.084 = [-0.134,0.034]

b) With 95% confidence, we can say that it is possible that the gaskets from shift 2 are, on average, wider than the gaskets from shift 1, because the mean difference extends to the negative interval or that the gaskets from shift 1 are wider, because the confidence interval extends to the positive interval.

c) Increasing the sample sizes results in a smaller margin of error, which gives us a narrower confidence interval, thus giving us a good idea of what the true mean difference is.

6 0
2 years ago
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