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Snezhnost [94]
2 years ago
9

If you have a stack of pennies without counting them how do you know if there is an even or odd number of them

Mathematics
1 answer:
zavuch27 [327]2 years ago
5 0

If I have a stack of pennies. And I have to tell that without counting whether there are even number of pennies or odd.

Even numbers are the numbers which are divisible by 2 and odd numbers are the numbers which are not divisible by 2.

Then I will put the given pennies in 2 rows and then I will match them to form a pair of 2 pennies. After matching, if there is 1 penny left over, then there is an odd number of pennies and if all the pennies have a match,then there is an even number of pennies.

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A direct variation function contains the points (2,14) and (4,38) which equation represents the function
Dmitry [639]
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A line through (2,14) and (4,38) is NOT direct variation, because the line connecting those two points does NOT pass through the origin, and thus has a vertical intercept.
3 0
2 years ago
The graph shows the linear relationship between the height of a plant (in centimeters) and the time (in weeks) that the plant ha
bija089 [108]
I found a graph with the same problem, so I guess this is the graph to be based on. To find the rate, just determine the slope between any two points along the line. Suppose these points are: (30,10) and (50,20).

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<em>The correct answer should be: the rate of change is 1 cm per 2 weeks, or 1/2.</em>

5 0
2 years ago
Read 2 more answers
Neptune’s average distance from the sun is 4.503 x 10e9 km. Mercury’s average distance from the sun is 5.791 x10e9 km.about how
Igoryamba

Answer:

77.76 times

Step-by-step explanation:

The average distance of Neptune  from the sun

= 4.503  ×  10 ⁹  k m .

and Mercury  =  5.791  ×  10 ⁷ k m .

Hence neptune is (  4.503  ×  10 ⁹) ÷ (5.791 × 10 ⁷  ) times farther from the sun than mercury

i.e.(  \frac{4.503}{5.791} )  × 10⁹⁻⁷ times

=   0.7776  ×  10 ² times

=   77.76  times.

4 0
2 years ago
The growth of a species of fish in a lake can be modeled by the function ƒ(x) = 500(1.10)x, where x is time in months since Janu
Lyrx [107]

Answer:

f(x) = 500(1.1)^x

And we want to know what repreent the value 500 for this equation. If we see the general expression for an exponential function we have:

y= ab^x

Where a is the constant or the initial amount, b te base and x the independnet variable (time)

For this special  case we know that:

a = 500, b =1.1

And 500 represent the constant or initial value for the function

Step-by-step explanation:

We have the following function given:

f(x) = 500(1.1)^x

And we want to know what repreent the value 500 for this equation. If we see the general expression for an exponential function we have:

y= ab^x

Where a is the constant or the initial amount, b te base and x the independnet variable (time)

For this special  case we know that:

a = 500, b =1.1

And 500 represent the constant or initial value for the function

6 0
2 years ago
Which expression can be used to find the sum of the polynomials?<br><br>(9 – 3x2) + (–8x2 + 4x + 5)
Wittaler [7]
9-3x2-8x2+4x+5=-11x2+4x+14
5 0
2 years ago
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