A random survey was taken in Centerville. People in twenty-five homes were asked how many cars were registered to their househol
d. The results are shown in the list below. 1, 2, 1, 0, 3, 4, 0, 1, 1, 1, 2, 2, 3, 2, 3, 2, 1, 4, 0, 0, 2, 2, 1, 1, 1 What is the mean, median, and mode of the Centerville data? a. 1.6, 1, 1 c. 1, 1, 1 b. 1.6, 2, 1 d. 2, 2, 2
In order to find the mean, you first count how many numbers are there. Then, you add all numbers together and divide them by the total of numbers. In this case, you would add (1+2+1+0+3+4+0+1+1+1+2+2+3+2+3+2+1+4+0+0+2+2+1+1+1), which equals to 40. The total of numbers is 25. You divide 40 by 25, and it would get you 1.6. Therefore, your mean is 1.6.
To calculate the median, you list the numbers from least to greatest, and find the middle number. The list for this survey would be 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4. The middle number of this list is 1, therefore, your median is 1.
The mode is simply the number that appears the most in this list. There are 4 zeroes, 9 ones, 7 twos, 3 threes, and 2 fours. The most in this list would be 1, because there are 9 of them. Your mode is 1.
You have to make a system of equations: lets make a equal the amount marry makes per student and b be her base amount. 90=15a+b (you have to subtract the top equation by the bottom equation) 62=8a+b (90-62=28, 15a-8a=7a, and b-b=0) Since b canceled out, you are left with 7a=28 which means a=4. you can than plug a into the equation 62=8a+b to find that b=30.
since Lisa makes half of the base amount marry, her base amount is 15. However, she also make twice the amount per kid so she makes 8 per kid. using the found values found you can make the equations (m=the amount Marry makes, l=the amount Lisa makes, and c is the number of children) m=4c+30 l=8c+15 set c=20 and you should get m=110 and l=175. Based off of that information, we can say that Lisa makes more money instructing a class of 20 students. I hope this helps.
