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dedylja [7]
2 years ago
14

There is a sidewalk of width x around a rectangular garden. If the garden measures twenty-feet by thirty-feet, then the combined

area of the garden and sidewalk is
Mathematics
1 answer:
prohojiy [21]2 years ago
5 0

Answer:

Area = 200 + 50 + x

Step-by-step explanation:

Given

Length = 20

Width = 30

Side Walk = x

Required

Determine the area.

To do this we need to get the new worth and length by adding the length of the sidewalk.

This gives:

Length = 20 + x.

Width = 30 + x

So, area becomes.

Area = (20 + x)(30 + x)

Area = 600 + 20x + 30x + x²

Area = 200 + 50 + x²

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Students are asked to memorize a list of 100 words. The students are given periodic quizzes to see how many words they have memo
Yuri [45]

Answer:

C. dL/dt=k(100−L)

Step-by-step explanation:

The rate of change of the number of words memorized is proportional to the number of words left to be memorized.

The rate of change is dL/dt.

The rate is a constant k. Since the rate is proportional to the number of words left to be memorized, and the initial number of words is 100, k has to be multiplied by (100-L).

So the correct answer is:

C. dL/dt=k(100−L)

6 0
2 years ago
What is the absolute value of the complex number -4-√2i?
nataly862011 [7]
Hello : 
| -4-√2i | = √((-4)² +(-√2)²) =√(16+2) =√18 = √(9×2) = √9 × √2 = 3<span>√2.. (answer B)</span>
4 0
1 year ago
Read 2 more answers
Frank and Gertrude mow lawns for extra money over the summer. Frank's income is determined by f(x) = 5x + 15, where x is the num
Nikitich [7]
Find h(x)
f(x)+g(x)=5x+15+4x+20=9x+35

ok so if gertrude works 4
f(x)=5x+15
f(4)=5(4)+15
f(4)=35

if we input 4 for x in f(x) to find how much made togethe rin 4 hours
h(4)=9x+35
h(4)=9(4)+35
h(4)=36+35
h(4)=71

split evenly?
71/2=35.5

frankalone=35 for 4 hours
frankwithgertrued=35.5 for 4 hours
slightly bettewr with gerturde
5 0
2 years ago
What would be Kelly’s weight be in newtons if her mass is 70 kilograms?
notsponge [240]
A. 70 × g
B. 70/g
C. 70/g2
D. 70 × g2
E. 70

answer= A
4 0
1 year ago
Is finding the value for the variable the only solution to real-world problems? Explain.
loris [4]

No. In many real-world scenarios, the variable is a value that is compared to other quantities. The value for the variable is used to find the quantities it is compared to.

5 0
1 year ago
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